An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is its acceleration?
deltaX=V naught t + (1/2)at^2)
The Attempt at a Solution
2(X-Vt)/t^2 = a
I rewrote the equation and plugged in the variables... Didn't seem to get the right answer. I'm all out of ideas... I really don't know where to go from there... I've spent 30mins on this problem so far.