Finding Acceleration in Circular Kinematics without Degrees or Radians

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Homework Help Overview

The discussion revolves around a circular kinematics problem involving the calculation of acceleration given a radius and rotational speed. The original poster has calculated the velocity and is now seeking to determine the acceleration without using degrees, only radians.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for centripetal acceleration and question the validity of the calculated acceleration value, considering the high speed of rotation.

Discussion Status

Some participants have provided guidance on the relevant equations for centripetal acceleration, while others are exploring the implications of the calculated acceleration value in the context of the problem's parameters.

Contextual Notes

The original poster is constrained by the requirement to use radians and is working within the context of circular motion, specifically focusing on the implications of high rotational speeds.

rottweiler
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1. I have a circular kinematics question that I am not sure how to solve part of. I have a radius of.27m, and the wheel rotates three full circles a second. The first part of the question asked me to solve for velocity and I got 5.09m/s. I have to find acceleration in m/s^2. I am not allowed to use degrees only radians.



2. The four kinematics equations rearranged for polar coordinates.



3. Part one was ((2*Pi*3*27m)=5.09m/s I am not sure how to proceed with the acceleration[/b
 
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Do you know the equation governing centripetal acceleration?
 
(V^2)/r but that would make the acceleration 96.0 m/s^2 isn't that a large acceleration?
 
Last edited:
rottweiler said:
(V^2)/r but that would make the acceleration 96.0 m/s^2 isn't that a large acceleration?

yes that is what it would be, but you must realize that it is making 3 revolutions in 1 second. which is quite fast.
 
Thank you so much!
 

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