A 1,300-N crate is being pulled across a level floor at a constant speed by a force of 310 N at an angle of 20.0° above the horizontal. If coefficient of kinetic friction is 0.207, find the acceleration of the crate.
The Attempt at a Solution
Fk=(uk)(N) = (0.207)(1300-310sin20) = 247.15 N
sumFx= Fx-Fk =310cos20-247.15 = 44.15 N
a=44.15/1300 =0.0340 m/s^2
Answer says a=0.331
Can someone point out what I did wrong? Thanks