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## Homework Statement

A 1,300-N crate is being pulled across a level floor at a constant speed by a force of 310 N at an angle of 20.0° above the horizontal. If coefficient of kinetic friction is 0.207, find the acceleration of the crate.

## Homework Equations

Fk= (uk)(N)

F=ma

## The Attempt at a Solution

Fx= 310cos20

Fy= 310sin20

N=1300-310sin20

Fk=(uk)(N) = (0.207)(1300-310sin20) = 247.15 N

sumFx= Fx-Fk =310cos20-247.15 = 44.15 N

F=ma=44.15

a=44.15/1300 =0.0340 m/s^2

Answer says a=0.331

Can someone point out what I did wrong? Thanks

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