Kinetic friction and acceleration

[pumpernickel]

Hello everyone, I would appreciate some help with this problem:

The coefficient of kinetic friction between the 1.2 kg block in the figure below and the table is 0.38. What is the acceleration of the 1.2 kg block?

Homework Equations

F=M*A
Fk = μk * N

The Attempt at a Solution

I created freebody diagrams and came up with these

Block A: +T1 - WAE = Ma * a
Block B: + T2 - T1 - fk = Mb * a
Block C: + WCE - T2 = Mc * a

So I combined equations and came up with

WCE - WAE - fk = (Ma * a)+(Mb * a)+(Mc * a)

and fk= μk * N

and I thought it would be .38*1.2*9.8

but I know I am doing something wrong I just don't know what

 

[PhanthomJay]

Looks ok to me...o wait I didn't check your combined equation..stand by...

Yes, looks good! Solve for a .

 

[pumpernickel]

Alright, I redid my algebra and that is where the problem was...I am rather embarrassed! Thank you for your help PhanthomJay.

 

[PhanthomJay]

Great, good work, welcome to PF!