Finding acceleration of pushed crate

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Homework Help Overview

The discussion revolves around calculating the acceleration of a crate being pushed across a level floor, considering forces such as applied force, friction, and gravitational force. The problem involves concepts from dynamics and friction in physics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the crate, including the applied force at an angle and the frictional force. There are attempts to calculate the net force and acceleration, with some participants questioning the inclusion of friction and the direction of forces.

Discussion Status

Several participants have provided guidance on recalculating forces and checking for errors in arithmetic. There is an ongoing exploration of the effects of friction and the correct application of forces in the x-direction. Some participants express uncertainty about the results, indicating a lack of consensus on the final answer.

Contextual Notes

Participants note the importance of considering both the x and y components of the forces, as well as the implications of the angle of the applied force on the acceleration of the crate. There is mention of a specific homework rule regarding significant figures in the final answer.

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Homework Statement


A 900 N crate is being pushed across a level floor by a force of 313 N at an angle of 25 degree above the horizontal. The coefficient of kinetic friction between the crate and the floor is 0.17. Acceleration of gravity is 9.81 m/s^2

http://img233.imageshack.us/img233/3717/31nk3.jpg

What is the acceleration of the box in m/s^2?

Homework Equations



F = ma

The Attempt at a Solution



Fg = 900 N
mass of crate = 91.743 kg
U = 0.17
g = 9.81 m/s^2
theta = 25
Fn = 900 + 132.2795
Ff = 0.17 * Fn = 175.4875

313cos 25 = 283.674 N
313sin 25 = 132.2795 N

Fx = ma
283.67 = 987.743a
a = 3.201 m/s^2

I didn't know whether or not to incorporate the y direction forces
 
Last edited by a moderator:
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Looks like you forgot to include friction.
 
Is the box moving up or down? What would this infer about acceleration?
 
Gannon said:
Is the box moving up or down? What would this infer about acceleration?

The box is moving left not up or down. Since the force is applied at an angle, the acceleration is not as great if applied directly horizontal
 
Doc Al said:
Looks like you forgot to include friction.

F = UFN
Friction = 0.17* (900 + 132.2795)
Friction = 175.4875 N
 
missashley said:
F = UFN
Friction = 0.17* (900 + 132.2795)
Friction = 175.4875 N
Good. Now recalculate the total force in the x-direction. (Which way does friction act?)
 
Doc Al said:
Good. Now recalculate the total force in the x-direction. (Which way does friction act?)

Friction act against the block, therefore, total force in x direction:

283.67 - 175.4875 = ma
111.1825 = 91.7431a
111.1825 / 91.7431 = a
a = 1.211889 m/s^2

did I do that right?
 
Looks good. (Round off your answer to a reasonable number of significant figures.)
 
I plugged it into the site where we're suppose to turn in our answers and it says it wrong. Hmmm
 
  • #10
arithmetic error!

missashley said:
283.67 - 175.4875 = ma
111.1825 = 91.7431a
Oops... double check that subtration. (Sorry for not catching that earlier.)
 
  • #11
yay it worked thanks so much! The answer is 1.179 m/s^2
 

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