Finding acceleration value for kinematic equation with t²

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Homework Statement


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Textbook problem 2.7 about a car at a traffic light, with position x(t) = bt^2 - ct^3, b = 2.40 m/s^2, c = 0.120 m/s^3, and parts (a) through (c) asking for average and instantaneous velocity and the time the car is at rest again.


Homework Equations



Kinematic equation x = x0 + v0x t + one half ax t squared, written as plain printed equation.


The Attempt at a Solution



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Hey, I did part a and b. Although I need a little help with part c.
I know you're supposed to solve for t^2 but I don't know what value to use for acceleration.
I'd use the quadratic formula to solve for t^2, but I'm just not sure which values to use...
At first I thought the initial velocity would be zero and the acceleration would be zero but then that left me with:

-1/2 * (4.8 m/s^2) = 0 which doesn't lead to the right answer. Could you guys point me in the right direction?
 
I ended up just differentiating then doing 0.36T^2 - 4.8T = 0 ---> (0.36T^2) / (0.36T) = (4.8t)/ (0.36T) which gave the right answer, but I wanted to know if there was a way to use the quadratic formula and the above equation since that's how the example in the book was done. I guess at this point its kind of an algebra question than a physics question.
 
You can't use the one dimensional equation you have given in the first post as in this case the acceleration is not constant.