Finding Activation Energy From Arrhenius Plot

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To find the activation energy from an Arrhenius plot, the user has plotted ln k against 1/T using half-life data at various temperatures. The temperatures range from 318 K to 338 K, with corresponding ln k values provided. The discussion shifts to the rate law, questioning why the concentration of H2O is often ignored, concluding that it is due to the reaction's rate being independent of H2O concentration as it is a liquid. This highlights the distinction between aqueous and liquid concentrations in rate laws. The conversation emphasizes the importance of understanding these concepts for accurate calculations of activation energy.
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Homework Statement



For a lab, I need to find the activation energy of an experiment from plotting the Arrhenius plot. I have the half-life time of the reaction at various temperatures.

Homework Equations



-Temperature (K)
318
322
327
331
338

-ln k
-6.17
-5.89
-5.65
-5.33
-5.01

-1/T
3.145 x 10^-3
3.106 x 10^-3
3.058 x 10^-3
3.021 x 10^-3
2.956 x 10^-3

The Attempt at a Solution



So far I've plotted ln k vs 1/T.
 
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Ok forget that. why would the concentration of H2O be ignored in a rate law reaction?
 
Last edited:
It would be ignored if the rate of the reaction was independent of H2O concentration.
 
Because it is a (l) and we only consider the concentrations of (aq) solutions.
 

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