Finding Air and Ground Speed Using Trigonometry: A Pilot's Navigation Problem

  • Thread starter Thread starter clook
  • Start date Start date
  • Tags Tags
    Navigation Trig
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 7K views
clook
Messages
32
Reaction score
0

Homework Statement


A pilot wants to fly on a bearing of 68.2 degrees. By flying due east, he finds that 38 MPH, blowing from the south, puts him on the course. Find the air speed and ground speed.

Homework Equations


using law of sines/cosines, ambiguous case.

The Attempt at a Solution


Tried drawing a diagram according to the book, the one with grspeed/airspeed/wind direction/heading.

however, it seems like it's moving south and i would have to draw a different diagram to solve this.

i have NO idea where to start! this has stumped me. I'm not sure if i even have enough information to complete this problem. i just need a general idea of what kind of diagram i need to draw..
 
Physics news on Phys.org
clook said:
however, it seems like it's moving south and i would have to draw a different diagram to solve this.

The plane isn't moving south. The question states that, by flying due east, the wind (blowing from the south) ensures that the plane travels on the correct path of 68.2 degrees. How have you set up the diagram?

For the second part of the question, I don't know what the groundspeed means.
 
http://savemyfile.net//files/6/book.jpg

something similar to this
 
Last edited by a moderator:
Ahh, ok I get what you mean now! Ok, well try drawing a diagram similar to that. The heading is the direction in which the pilot flies, ie due east here. The true course is the direction the pilot wants to fly, ie 68.2 degrees. The wind is blowing from the south. Your triangle will be different to the one in the book, in that it will be a right angled triangle.
 
argh.. it would bea right triangle?

man, is there a way you could provide me some type of diagram for this?

edit: nvm, got it.
 
Last edited: