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Finding amplitude of oscillator

  1. Feb 23, 2009 #1
    1. The problem statement, all variables and given/known data
    a 200g mass attached to a horizontal spring oscillates at a frequency of 2.0 Hz. At t=0s, the mass is at x=5.0 cm and has v=-30 cm/s. Determine:
    a) period
    b)angular frequency
    c) AMPLITUDE


    2. Relevant equations
    x(t)=Acos(wt+psi)
    v(t)=-Awsin(wt+psi)
    w=2*pi*f
    T=1/f

    3. The attempt at a solution
    I have solved for the period=1/2 s
    I have also solved for angular frequency=2*pi*2=4*pi
    However, I am confused about solving for amplitude. I thought that I could plug in 0.05 m and 0s to the x(t) formula, but I do not know psi (phase constant) so I am stuck.
     
  2. jcsd
  3. Feb 24, 2009 #2
    When solving for the amplitude, try using conservation of energy.

    --> All energy in the system is potential energy when the spring is extended the most. (When the spring is extended the most, the lenght extended is the amplitude)

    The spring constant you can get from

    T=2*pi*sqrt(m/k)
     
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