Finding amplitude from simple harmonic equation function

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Homework Help Overview

The discussion revolves around the periodic motion described by the function f(t) = Acos(wt+φ), specifically focusing on determining the amplitude and phase constant for different functions: position x(t), velocity v(t), and acceleration a(t). Participants are exploring the implications of the harmonic oscillator's equations and the relationships between these functions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of amplitude and phase constant in the context of position, velocity, and acceleration functions. There is uncertainty about whether these constants remain the same across different representations of motion. Some participants suggest that amplitude and phase constant should be derived from initial conditions, while others question the relevance of the constants when transitioning between functions.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the relationships between amplitude and phase constants in different contexts. Some have offered clarifications regarding the definitions and implications of the equations, while others are still grappling with the concepts and seeking further understanding.

Contextual Notes

There is mention of potential confusion arising from the use of symbols such as A and φ, which may overlap with their meanings in the problem statement. Participants are encouraged to reconsider their assumptions about the constants when analyzing the velocity and acceleration functions.

vetgirl1990
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Homework Statement


The periodic motion is given in the form: f(t) = Acos(wt+φ)
What is the amplitude and phase constant for the harmonic oscillator when:

(a) f(t) represents position function x(t)
(b) f(t) represents velocity function v(t)
(c) f(t) represents acceleration function a(t)

Homework Equations


x(t) = Acos(wt+φ)
v(t) = -wAsin(wt+φ)
a(t) = -w2Acos(wt+φ)

The Attempt at a Solution


(a) To find amplitude from a position equation, I know that amplitude is the maximum displacement of the particle in harmonic oscillation, so A=x(t)
To get A=x(t), I would need my phase of motion to be zero, so that cos(wt+φ)=1. This would occur when φ=0 and t=0.
Therefore A=x and φ=0

However, I'm not really sure why it's relevant to ask the amplitude and phase constant for the velocity and acceleration functions. Both amplitude and phase constant (φ) are determined from initial conditions, so wouldn't the amplitude and phase constant be the same for x(t), v(t) and a(t), given that it's based off the same function?
 
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What about that factor ##\omega## or ##\omega^2## ?

Advice: replace the A in your relevant equations by some other letter. It interferes with the A in the problem statement !

Actually: same for the ##\phi##. The ##\phi## in the problem statement is to be treated as a given. You can't require it to be zero afterwards...
 
BvU said:
What about that factor ##\omega## or ##\omega^2## ?

Advice: replace the A in your relevant equations by some other letter. It interferes with the A in the problem statement !

Actually: same for the ##\phi##. The ##\phi## in the problem statement is to be treated as a given. You can't require it to be zero afterwards...

Sorry, I don't quite understand your reply. I just know that Amplitude and Phase constant need to be determined from initial conditions.
 
I fear you have not understood what you are asked to do.
For a), you are to take the position as specified by x(t)=A cos(ωt+φ). In terms of the symbols in that equation, what is the amplitude, and what is the phase? Yes, it's an extremely simple question, don't try to make it complicated.

b) and c) are where the interest lies. In b), the motion is now defined by v(t)=A cos(ωt+φ). This is still SHM, but clearly the constants in it no longer have their usual meanings. 'Amplitude' still refers to the variation in x(t), so in terms of the symbols in the v(t) equation given, what is the amplitude now?
 
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haruspex said:
I fear you have not understood what you are asked to do.
For a), you are to take the position as specified by x(t)=A cos(ωt+φ). In terms of the symbols in that equation, what is the amplitude, and what is the phase? Yes, it's an extremely simple question, don't try to make it complicated.

b) and c) are where the interest lies. In b), the motion is now defined by v(t)=A cos(ωt+φ). This is still SHM, but clearly the constants in it no longer have their usual meanings. 'Amplitude' still refers to the variation in x(t), so in terms of the symbols in the v(t) equation given, what is the amplitude now?

Ah I see what you mean... amplitude would still be "A". As in the same amplitude that was specified in the position equation.
 
I can't follow. If v(t)=A cos(ωt+φ), then surely x(t) is not A cos(ωt+φ), so the amplitude is not equal to A.
 
BvU said:
I can't follow. If v(t)=A cos(ωt+φ), then surely x(t) is not A cos(ωt+φ), so the amplitude is not equal to A.
Then I'm afraid I still don't understand.
 
If I understand the question correctly, you are supposed to obtain position function from each given function and then find the amplitude and phase constant.
 
vetgirl1990 said:
Then I'm afraid I still don't understand.
In b), you are given v(t)=A cos(ωt+φ). This defines the motion (up to a point) but do not assume that A stands for amplitude, etc.
Suppose x(t) is still SHM. Pick some new symbols to represent its amplitude, frequency and phase, then write out the equation for x(t) in terms of those. From that, obtain an equation for v(t), and compare it with the given equation.
 

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