Finding an equation for a plane containing 3 points

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yecko
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Homework Statement


螢幕快照 2017-09-30 下午3.37.01.png


Homework Equations


https://answers.yahoo.com/question/index?qid=20120204205204AAEvo8V

The Attempt at a Solution


771152855.jpg


This is my attempt following the solution in the yahoo answer, yet it is incorrect...
Can anyone tell me if I have made mistake in any of the manipulation?
Any help is appreciated~~
Thanks!
 
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I just multiplied the whole equation by -3 and manipulated all the signs... after i checked several times, i still can't find what is wrong...
 
yecko said:
I just multiplied the whole equation by -3 and manipulated all the signs... after i checked several times, i still can't find what is wrong...
Check the determinant.
 
@yecko, when you calculate a cross product, it's a good idea to make sure that the vector you get is actually perpendicular to the two input vectors you're working with. This can be done very quickly, using the dot product. In the work you did, your calculated cross-product is <2, 2, -1>. This vector isn't perpendicular to either of the other two vectors, which means your calculation is incorrect.