Finding Angle A in a Circular Arc: A Physics Trigonometry Problem

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Homework Help Overview

The discussion revolves around a physics problem involving trigonometry, specifically finding an angle A related to a circular arc, given the altitude and arc length. Participants are exploring the relationships between the angle, radius, and the properties of the triangle formed by the arc.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the angle A, the radius of the circle, and the lengths involved in the problem. Some question the assumptions about the hypotenuse being the radius based on the provided sketch. Others mention numerical solutions and ratios related to the sine function.

Discussion Status

The discussion is active, with participants providing insights into the relationships between the variables involved. Some guidance has been offered regarding the use of numerical solutions, and there is an acknowledgment of the complexity of solving the equations algebraically.

Contextual Notes

Participants are working with specific values for the arc length and altitude, and there is a mention of the need to measure angles in radians. The original poster has provided an image attachment for reference, which may contain additional context for the problem.

Arkronus
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Hello, I am currently in beginning physics and we are learning a lot about Trig onometry. A homework problem is really bugging me. Here's what it says:

Find the angle A, given the altitude and arc length of the figure shown:
(the picture is in the attachment and also some work i have done.)
 

Attachments

  • physics.GIF
    physics.GIF
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Physics news on Phys.org
testing if i can put the image on this post.
http://img222.imageshack.us/img222/6819/physicszw2.gif
 
Last edited by a moderator:
I can also solve it only numerically for the ratio

[tex]\frac{\sin(A)}{A}=0.719[/tex]

which gives A as 0.8658 radians
 
Last edited:
When you say you "believe the hypotenuse is the radius"... it doesn't look it in your sketch.
 
Last edited:
Basically, then, you have a circular arc, of length 4.17 cm. Dropping a perpendicular gives a length of 3 cm. Yes, the hypotenuse of the right triangle is a radius of the circle. sin A= 3/R and, as long as A is measured in radians, RA= 4.17. Since R= 4.17/A, putting that into the first equation you have sin A= 3A/4.17 just as you say. There is no "algebraic" way of solving such an equation. A numerical solution is the best you can do.
 

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