Finding $\angle ADC$ in $\triangle ABC$

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Discussion Overview

The discussion revolves around finding the angle $\angle ADC$ in an isosceles triangle $\triangle ABC$ where $\overline{AB} = \overline{AC}$, and an inner point $D$ satisfies specific conditions regarding the lengths and angles within the triangle.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • Post 1 presents the problem statement, outlining the conditions of the triangle and the goal of finding $\angle ADC$.
  • Post 2 and Post 3 inquire about the nature of the problems, questioning whether they are for assistance or for members to attempt independently.
  • Post 4 reiterates the problem statement and indicates that the poster has a solution, although the solution is not provided.

Areas of Agreement / Disagreement

There is no consensus on the solution to the problem, and multiple perspectives on the nature of the discussion are present, with some participants seeking clarification on the purpose of the problems.

Contextual Notes

The discussion lacks specific mathematical steps or solutions, and the assumptions regarding the configuration of points and angles are not fully explored.

Albert1
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$\triangle ABC, \overline{AB}=\overline {AC}$,there exists an inner point ${D}$ and satisfyng :
(1)$\overline {AB}=\overline {AC}=\overline {BD}$
(2)$\angle DCB=30^o$
find $\angle ADC=?$
 
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Are these problems you need help with? Or are they just for members to try?
 
Joppy said:
Are these problems you need help with? Or are they just for members to try?

for members to try
 
Albert said:
$\triangle ABC, \overline{AB}=\overline {AC}$,there exists an inner point ${D}$ and satisfyng :
(1)$\overline {AB}=\overline {AC}=\overline {BD}$
(2)$\angle DCB=30^o$
find $\angle ADC=?$
my solution
explanation :
GD//BC
let DE=GH=1,
EF=FH=x,
AK=y
$\angle DEC=\angle GHB=90^o$
Triangle AGD is an equilateral triangle

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