Finding average speed given two velocities, help

In summary, the average speed of a person walking from point A to point B at a speed of 47.0m/s and then back to point A at a speed of 3.10m/s is not 3.9m/s as initially attempted. The correct method is to find the total time it took to cover twice the distance of AB, which can then be divided into the total distance traveled to get the average speed.
  • #1
steph35
11
0

Homework Statement


A person walks first at a constant speed of 47.0m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.10m/s


Homework Equations


What is her average speed over the entire trip?


The Attempt at a Solution


I tried (4.70m/s + 3.10m/s)/2 to get the average and got 3.9m/s but it was wrong...I can't really think of anything else b/c time isn't given...
 
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  • #2
steph35 said:

Homework Statement


A person walks first at a constant speed of 47.0m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.10m/s


Homework Equations


What is her average speed over the entire trip?


The Attempt at a Solution


I tried (4.70m/s + 3.10m/s)/2 to get the average and got 3.9m/s but it was wrong...I can't really think of anything else b/c time isn't given...

The average speed is the distance traveled divided by time.
Your answer is for equal time intervals at different speeds.
But you have unequal time intervals.
You need to find the total time that it took to go twice the AB distance.
 
  • #3


As a scientist, it is important to understand that average speed is calculated by dividing the total distance traveled by the total time taken. In this scenario, we can calculate the total distance by adding the distance from A to B (which is the same as the distance from B to A) and the total time by adding the time taken to travel from A to B and back from B to A.

So, the total distance traveled would be 2*(47.0m/s)*t, where t is the time taken for the round trip. Similarly, the total time taken would be t + t = 2t.

Therefore, the average speed can be calculated as (2*(47.0m/s)*t)/(2t) = 47.0m/s.

It is important to note that the units for average speed will be in meters per second (m/s) since we are dividing distance (m) by time (s).

In summary, the average speed for this scenario is 47.0m/s. It is crucial to understand the concept of average speed and how it is calculated in order to accurately solve problems like this. Additionally, it is important to always include units in your calculations and final answer to ensure accuracy.
 

1. What is average speed?

Average speed is a measure of the distance traveled divided by the time it took to travel that distance. It is a scalar quantity and is usually represented in units of distance per time (e.g. miles per hour, kilometers per hour).

2. How do you calculate average speed?

To find the average speed given two velocities, you can use the formula: average speed = total distance traveled / total time taken. Make sure to use the same units for distance and time in order to get the correct result.

3. Can average speed be negative?

No, average speed cannot be negative. It is always a positive quantity, as it represents the total distance traveled divided by the total time taken, regardless of the direction of travel.

4. What is the difference between average speed and instantaneous speed?

Average speed is the overall speed over a given distance and time, whereas instantaneous speed is the speed at a specific moment in time. Average speed takes into account the total distance traveled, while instantaneous speed only considers the speed at a specific point in the journey.

5. Can average speed be greater than the highest velocity?

Yes, it is possible for the average speed to be greater than the highest velocity, as long as the two velocities are in opposite directions. This is because average speed takes into account the total distance traveled, while velocity only considers the speed at a specific moment in time.

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