1. The problem statement, all variables and given/known data A 100 μμF capacitor, C1, is charged to a potential difference of 50 Volts. The charging battery is disconnected and the capacitor is connected to a second uncharged capacitor, C2. If the potential across C1 drops to 35 volts, what is the capacitance of C2? 2. Relevant equations Q = CeqΔV 3. The attempt at a solution Q = CeqΔV Q = (C1 + C2)ΔV Q = (100x10-12F + C2)(-15V) I am confused on what to do from this point on, what do I do with the Q?