(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 100 μμF capacitor, C1, is charged to a potential difference of 50 Volts. The charging battery is disconnected and the capacitor is connected to a second uncharged capacitor, C2. If the potential across C1 drops to 35 volts, what is the capacitance of C2?

2. Relevant equations

Q = C_{eq}ΔV

3. The attempt at a solution

Q = C_{eq}ΔV

Q = (C_{1}+ C_{2})ΔV

Q = (100x10^{-12}F + C_{2})(-15V)

I am confused on what to do from this point on, what do I do with the Q?

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# Homework Help: Finding Capacitance of a capacitor

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