Finding center of mass of a picture

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Homework Help Overview

The discussion revolves around finding the coordinates of the center of mass (CoM) of a uniform sheet of steel, with specific reference to a problem involving increments of 6. The original poster expresses difficulty in determining the x and y coordinates in preparation for an upcoming exam.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition of the center of mass and suggest decomposing the problem into x and y components. There are suggestions to analyze the CoM in each direction separately and to visualize the distribution of mass to find the point of equilibrium.

Discussion Status

The discussion includes various interpretations of how to approach the problem, with participants offering different methods for calculating the center of mass. Some guidance has been provided on breaking down the problem into manageable parts, but there is no explicit consensus on a single method.

Contextual Notes

The original poster is preparing for an exam, indicating a time constraint that may affect the depth of exploration in the discussion.

runawayshoes
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hey everyone, I am stumped as to finding the x and y coords of the center of mass of this picture. it is supposed to be a uniform sheet of steel in increments of 6. please help, i have an exam tomorrow.

p9-41alt.gif
 
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What exactly is the centre of mass?

Once you have the answer, you can "decompose" it into two components, x and y. So you'd basilcally find the centre line along x, then along y, and your centre point would be the intersection of the two.
 
i'm still stumped heh
 
Find the CoM in each direction separately. Meaning stack all the blocks so that you only have one direction to deal with at a time. For example, imagine a figure with 3m on the left column, 2m in the middle column, and 1m on the right column (where m is the mass of one block). then find the center of mass of those 3 blocks, this corresponds to the CoM in the x direction. Do something similar for the y direction.
 
The centre of mass is a point around which all the mass is symmetrically arranged.

Take the x direction for example. For what value of x would the mass be symmetrically distributed, i.e. you have the same mass to the right and to the left of your x value?

Note that if you balance your plate on a knife edge placed at that x, the plate would be in equilibrium.
 
i got it, thanks. answer is (7,8) btw
 

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