Finding COM, and inertia my answers don't make sense?

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SUMMARY

The discussion focuses on finding the center of mass (COM) and rotational inertia of a system comprising four masses: m1=2.5kg, m2=5kg, m3=2.5kg, and m4=5kg. The correct approach involves calculating the COM using the formula Xcom = (m1d1x + m2d2x + m3d3x + m4d4x) / M, where M is the total mass. The rotational inertia about the x-axis is calculated using ICOM = Σmiri2, leading to a final COM position of (Xcom, Ycom, Zcom) and a rotational inertia of 60 kg·m².

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  • Understanding of center of mass (COM) calculations
  • Knowledge of rotational inertia concepts
  • Familiarity with mass distribution and coordinates
  • Basic algebra for solving equations
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  • Study the derivation of the center of mass formula in multi-body systems
  • Learn about rotational inertia calculations for different shapes and axes
  • Explore the impact of mass distribution on the center of mass
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Finding COM, and inertia please help my answers don't make sense??

Homework Statement



Find the center of mass of the object shown in the figure below?

LINK TO FIGURE:
http://s1168.photobucket.com/albums/r497/amy_parker1/?action=view&current=Untitled.jpg

1. Find the center of mass of the object shown in the figure below.

2. Calculate the rotational inertia of the object about the x-axis.

3. From this value, deduce the rotational inertia of the object about an axis parallel to the x-axis, and going through the center of mass.

m1=2.5kg , m2=5kg, m3=2.5kg , m4=5kg

Homework Equations



COM

Inertia?

The Attempt at a Solution



my answers don't make sense

for COM I got 2
 
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Hi amyparker30! Where are your answers? Where is your working?
 


ok, my answers are totally wrong but for COM 1 got (2(2.5+5+2.5+5))/15 = 2

ICOM=Rotational Inertia = 2^2(2.5+5+5+2.5) = 60

i bet these are 100% wrong what should I do, my teacher wouldn't help me and the people from class just skipped this question :(
 


Ok first you need to understand the COM formula and see how it works. Basically you need to specify a coordinate to tell where the COM is. That means you need to find the center of mass in the x direction, y direction, and z direction of the system or object.
So we start by separating everything in components( x, y and z). Let's do the x direction first.

We let d_{nx} represent the distance in the x direction for each particle (n=1,2,3,4)
Then
X_{com} = \frac{m_2 d_{2x}+m_3 d_{3x} + m_1 d_{1x}+m_4 d_{4x}}{M}
where M is the total mass. Note that
d_{2x}=d_{1x}=0
and
d_{3x}=d_{4x}=2 m

Similarly for y:
Y_{com} = \frac{m_2 d_{2y}+m_3 d_{3y} + m_1 d_{1y}+m_4 d_{4y}}{M}
Note that
d_{2y}=d_{3y}=0
d_{1y}=d_{4y} = 2 m

Similarly for z:
Z_{com} = \frac{m_2 d_{2z}+m_3 d_{3z} + m_1 d_{1z}+m_4 d_{4z}}{M}
But Note that
d_{1z} = d_{2z} = d_{3z} = d_{4z} = 0
then
Z_{com} = 0

Then at the end you get the COM to be at (X_{com},Y_{com},Z_{com})

Now try to plug in the numbers and see what you get. (Easy! =))

Do the same thing for the next part (moment of inertia), first understand the formula/equation and just follow it slowly.
 
Last edited:


I think the first part of this question would be a good one for a multiple choice test. :smile:

By symmetry, the CoM of the two equal masses m1 and m2 is mid-way between them. Likewise, the CoM of the equal mass pair m3 and m4 is mid-way between m3 and m4. And you wouldn't believe our luck :wink: but those two CoM locations coincide!
1OqIj.gif


So that surely must be the CoM for the 4 bodies.
 

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