Finding Components of Vectors in a Crystal Lattice

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SUMMARY

The discussion focuses on determining the components of three lattice vectors (a, b, c) in a crystal lattice, each with a magnitude of 10.5 Angstroms and angles of 109.5 degrees between them. The solution involves setting vector a as {10.5, 0.0, 0.0} and vector b in the 1-2 plane as {10.5 cos(109.5), 10.5 sin(109.5), 0.0}. Vector c can be derived using spherical trigonometry, specifically by solving a spherical right triangle formed by the heads of vectors a and c and a midpoint between the heads of vectors a and b.

PREREQUISITES
  • Understanding of vector representation in three-dimensional space
  • Knowledge of trigonometric functions and their applications in vector calculations
  • Familiarity with spherical trigonometry concepts
  • Basic principles of crystal lattice structures
NEXT STEPS
  • Study the application of spherical trigonometry in vector calculations
  • Learn about the geometric interpretation of crystal lattice structures
  • Explore the use of trigonometric functions in three-dimensional vector projections
  • Investigate the properties of angles and lengths in crystal lattices
USEFUL FOR

Students in materials science, physicists studying crystallography, and anyone involved in computational modeling of crystal structures will benefit from this discussion.

Eduard1
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Homework Statement



Be the vectors a, b, c such as:

| a | = | b | = | c | = 10.5 Angstron

The angles between these vectors are:

alpha = beta = gamma = 109.5 degree

These vectors represent the lattice vectors of a crystal.

Find out their components (a_1, a_2, a_3, b_1, b_2, b_3, c_1, c_2, c_3).

Homework Equations





The Attempt at a Solution



So, we know the length of the vectors and the angle between them. We want to find out the components of each vector. I know one has to use the trigonometric functions, but I am not sure how. Should I project the vector a on b (to find a_2) and on c (to find a_3) ? Or how do I find the components of a ?

Thank you very much for any fast answer/hint/suggestion,
Eduard
 
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Looks like one of the vectors can be arbitrary, so let a = {10.5, 0.0, 0.0}. Vector b can be assumed to lie in the 1-2 plane without loss of generality, so let b = {10.5 cos(109.5), 10.5 sin(109.5), 0.0}.

You can find vector c using spherical trigonometry. The most expedient way appears to be to solve the spherical right triangle consisting of the head of vector a, the head of vector c, and a point half-way between the heads of vectors a and b. Hope that helps!
 

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