Finding concentration of Permanganate

[lcary]

Homework Statement

Calculate the KMnO₄ concentration of the solution in the cuvet. The Solution in the covet was made by mixing 5.00 ml of 1.00 M H₂SO₄ and 1.00 ml of the stock 2.00x10^-3 M KMnO₄.

Homework Equations

m1v1=m2v2

The Attempt at a Solution

I've tried using the dilution formula m1v1=m2v2 to find the answer with no luck. First I tried the following: 2.00x10^-3 M * 0.001L = m2 * 0.006L. I solved for m2 and the program said my answer was incorrect, I've quadruple checked to make sure I didn't make a simple mistake. Then I tried to figure out how many moles were in 1ml of a 2.00x10^-3 Molar solution but then I realized this still wouldn't give me the concentration and I wouldn't know where to go next with the value I obtained. I don't know what else to try. Help please.

 

[symbolipoint]

The potassium permanganate was diluted to one sixth of the original value. You added 5 parts containing no permanganate to one part containing permanganate. That is 6 parts of added liquids from which only one part contained permanganate.

 

[Borek]

First I tried the following: 2.00x10^-3 M * 0.001L = m2 * 0.006L. I solved for m2 and the program said my answer was incorrect

Your approach is correct. Either you are entering incorrect number of significant figures, or program accepting answer expects the number in different format, but (unless you solved for m2 incorrectly) you should get the correct result.

 

[lcary]

Your approach is correct. Either you are entering incorrect number of significant figures, or program accepting answer expects the number in different format, but (unless you solved for m2 incorrectly) you should get the correct result.

Thank you for replying. I wasn't entering in the correct number of significant figures, once I corrected for the error, I got the right answer.

 

[DeeNos]

As a scientist, it is important to approach problems like this with a clear and logical thought process. Here are some steps you can follow to find the concentration of the KMnO4 solution in the cuvet:

1. Start by writing down all the given information and units:
- Volume of H2SO4 = 5.00 mL
- Concentration of H2SO4 = 1.00 M
- Volume of stock KMnO4 solution = 1.00 mL
- Concentration of stock KMnO4 solution = 2.00x10-3 M

2. Use the dilution formula (m1v1 = m2v2) to calculate the concentration of the diluted KMnO4 solution in the cuvet. Remember to convert all volumes to liters:
(1.00 M)(5.00 mL) = (m2)(1.00 mL)
m2 = (1.00 M)(5.00 mL)/(1.00 mL) = 5.00 M

3. This is the concentration of the diluted KMnO4 solution. However, we need to find the concentration of the stock KMnO4 solution. To do this, we can use the formula for dilution again:
(m1v1 = m2v2)
(5.00 M)(1.00 mL) = (m2)(1.00 mL)
m2 = 5.00 M

4. Now, we know the concentration of the stock KMnO4 solution (2.00x10-3 M) and the concentration of the diluted KMnO4 solution (5.00 M). We can use these values to find the concentration of the KMnO4 solution in the cuvet. To do this, we can use the following formula:
M1V1 = M2V2
(2.00x10-3 M)(1.00 mL) = (M2)(6.00 mL)
M2 = (2.00x10-3 M)(1.00 mL)/(6.00 mL) = 3.33x10-4 M

5. Therefore, the concentration of the KMnO4 solution in the cuvet is 3.33x10-4 M. Remember to always check your units and make sure they are consistent throughout the calculation. Also, be careful with