Finding Convergence, Limits and values

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    Convergence Limits
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Homework Help Overview

The discussion revolves around determining the convergence of the sequence {an} defined by an=(3n+(-1)n)/(n^3+2) as n approaches infinity. Participants are exploring the implications of the limit and the concept of convergence versus divergence.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the confusion surrounding the term -1^n and its impact on the sequence. Some suggest evaluating the limit by substituting large values for n, while others question the understanding of convergence and divergence.

Discussion Status

The conversation is ongoing, with some participants providing guidance on evaluating limits and clarifying concepts. There is a mix of interpretations regarding the results and definitions, with no explicit consensus reached yet.

Contextual Notes

Some participants express uncertainty about their understanding of limits and the definitions of convergence and divergence, indicating a need for foundational clarification. The original poster acknowledges confusion and seeks assistance in grasping these concepts.

smutangama
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Don't really know how to get round this, the -1^n confuses me.

Homework Statement



Determine whether the following sequence {an} converges as n→∞?
if it does, find limn→∞an

Homework Equations



an=(3n+(-1)n )/ (n3+2)

Homework Statement


 
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What is your purpose in posting this? It does not appear to be to get an answer or for help because you have made no to do it yourself- so you are clearly not very interested in the answer!

An obvious first step, since it asks for "the limit as n goes to infinity" would be to see what you get if you replace n with some really large number- say 10000000. Have you tried that?
 
I'm sorry, I'll post better next time. I'm new to the site and still trying to get used to things. I am not really good at limits. It confuses me.
I needed help with the question, I came up with zero at the end but I wasn't sure if I was right.
Also does this mean it diverges?
 
Can you explain how you found ##0##?
 
I used a method where I divided the numerator and denominator by the highest power which was n^3. From there I was left with 0/1 which is zero. Was that right?
 
smutangama said:
I'm sorry, I'll post better next time. I'm new to the site and still trying to get used to things. I am not really good at limits. It confuses me.
I needed help with the question, I came up with zero at the end but I wasn't sure if I was right.
Also does this mean it diverges?
What is your understanding of the words "converge" and "diverge"? You seem to be saying that "because the limit is 0, it diverges". Is that what you are saying?
 
my understanding is if it converges, the total sum is the limit of the sequence or something along those lines. Maybe I just have the entire concept wrong, that's why I'm finding it confusing. Can you please help me with a simple explanation of the two?
 

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