Finding current in a parralle wire

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SUMMARY

The discussion centers on calculating the current in two parallel wires carrying equal but opposite currents, separated by 8.0 cm, with a magnetic field of 0.01 T at point P, located 2 cm from wire 1. The relevant equation used is B = (μ.I)/(2πr), where μ is 4π x 10^-7 T·m/A. The correct approach involves recognizing that the magnetic field at point P is the superposition of the magnetic fields from both wires, leading to the equation B_{p} = (μ I)/(2π r_{1}) + (μ I)/(2π r_{2}).

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Homework Statement



two long straight parallel wires separated by 8.0 cm carry currents of equal magnitude but heading in opposite directions. Wires are perpendicular to the plane of the page. Point P is 2cm form wire 1. magnetic field at P = 0.01 T directed downward ( neg y direction). Calc Current in wire 1 and its direction.


Homework Equations




B= (μ.I)/2 pi r where mu not is 4pi X 10^-7 and r is the distance of the mag field from the wire.

The Attempt at a Solution



I tried using the given information and instead of solving for B solve for I (current) However my answer was incorrect.

Did i miss a step?

Thank You
 
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You have not been very clear in showing your entire approach.
However, I believe that the likely mistake that you made is overlooking the fact that the magnetic field of 0.01 T at P is the superposition of the individual magnetic fields from wires 1 and 2. Thus,
[tex]B_{p} = \frac{μ I}{2 \pi r_{1}} + \frac{μ I}{2 \pi r_{2}}[/tex]
where [itex]r_{1}[/itex] denotes distance from wire 1 to P and [itex]r_{2}[/itex] denotes distance from wire 2 to P.
 
Thank you :) that's helps a ton
 

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