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Finding Current in a series circuit

  1. Sep 29, 2009 #1
    1. The problem statement, all variables and given/known data

    An ideal voltmeter is connected to a 2.0 Omega resistor and a battery with emf 5.0V and internal resistance 0.5 Omega

    Series Circuit

    YF-25-35.jpg

    2. Relevant equations

    V=IR
    V=I(R1+R2)
    R(total)=R1+R2


    3. The attempt at a solution

    5.0V=I(.5 Ohms + 2.0 Ohms)

    solve for I because current is conserved through a series circuit

    I=2amps.....this is wrong.
     
    Last edited: Sep 29, 2009
  2. jcsd
  3. Sep 29, 2009 #2

    Delphi51

    User Avatar
    Homework Helper

    There is something very odd about this circuit. A voltmeter is designed to only let a tiny current (ideally just one electron per second) through in order to measure the energy per charge (Voltage). Thus practically no current will flow around the circuit.

    It isn't a sensible question with the information given. Better check the question again. Incidentally, you didn't list any actual questions.
     
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