Finding derivative of x^x using limit definition

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SUMMARY

The discussion focuses on finding the derivative of the function x^x using the limit definition. The key limit expression discussed is lim [(x+h)^h - 1]/h as h approaches 0, which equals ln(x). Participants emphasize the importance of the exponential and logarithmic relationships, specifically using e^{ln(x)} = x and the Taylor series expansion for log(1+h) to derive the result. The conversation highlights the application of these mathematical concepts to successfully compute the derivative.

PREREQUISITES
  • Understanding of limit definitions in calculus
  • Familiarity with exponential functions and logarithms
  • Knowledge of Taylor series expansions
  • Basic proficiency in mathematical notation and manipulation
NEXT STEPS
  • Study the derivation of exponential functions using limits
  • Explore Taylor series and their applications in calculus
  • Learn about the properties of logarithms, particularly natural logarithms
  • Investigate advanced techniques in differentiation, such as implicit differentiation
USEFUL FOR

Students studying calculus, mathematicians interested in derivatives, and educators teaching advanced calculus concepts will benefit from this discussion.

scottshannon
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I am trying to find the derivative of x^x using the limit definition and am unable to follow what I have read. Can someone help me understand why lim [(x+h)^h -1]/h as h ---> 0 = ln(x). This part of the derivatio
 

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Try using the fact that e^{ln(x)}=x
 
Limit (a∧h) = 1 + h×log(a)/1! + ((h×log(a))∧2)/2! + ...
h→0

For the steps performed on the right side , use , as already said , x = e∧log(x) ,
and

Limit (log(1+h)) = h - (h∧2)/2 + (h∧3)/3 - ...
h→0

*Log is taken to base e .
 

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