Finding distance through a velocity-time

[Becca93]

Homework Statement

The graph attached shows the speed of a car traveling in a straight line as a function of time. The value of Vc is 4.00 m/s and the value of Vd is 7.00 m/s. Calculate the distance traveled by the car from a time of 0.60 to 6.40 seconds.


2&3. Relevant equations + Attempt at a solution
I know that the distance is the area under the graph. My and from t=1s to t=6.4s, I have the total. It's from t=0.6s to t=1s that I don't understand how to get.

 

[Delphi51]

You have a straight line on the graph for the first second, so the acceleration is constant. You can find it (slope), then use an accelerated motion formula to find the velocity at time 0.6 s. Or use linear interpolation - 60% of the t=1 speed at t =0.6.

That leaves you with finding the area under the trapezoid from 0.6 to 1 s. Look up the formula in wikipedia if you don't know it. Or split it into a rectangle plus a triangle and use area formulas you do know.