Finding total distance from velocity-time graph with trapezium method

[Eobardrush]

Homework Statement

Find the total distance travelled in the first 16 seconds

Relevant Equations

s=0.5(a+b)*h

So I am supposed to look at the graph at part C and determine the total distance travelled. This is the answer sheet of the textbook. But I feel like the textbook is wrong here. But then I needed a confirmation if others can agree that it is wrong or not cause now I am very confused.

My answer is as follows

I divided this into two trapeziums.
1st Trapezium from the left:

s=0.5(15+55)*10

2nd Trapezium next to it:

s=0.5(55+37)*6

And then I add both of these trapezium area for the total distance.

So my answer is= 626m

The problem is that I am not sure why there is a 15 in the answer sheet for the 2nd Trapezium(for the variable "a" in the trapezium area equation). I think it is wrong. But maybe am I missing something?

Note v is given in ms^-1
t is given in seconds

 

[Orodruin]

Obvious typo/slip on the solver’s part.

 

[Eobardrush]

Obvious typo/slip on the solver’s part.

Ah thank god. Thanks for confirming for me. Else I would have been spending the whole day trying to figure out why there is a 15 there haha.
This is the first time seeing a mistake in this textbook. But I guess things like this happen

 

[kuruman]

This is the first time seeing a mistake in this textbook. But I guess things like this happen

They do happen and it's a good idea to bear that in mind. What drew me to science is that when you're right, you're right and it's not contingent on someone else's opinion.

 

[Orodruin]

when you're right, you're right and it's not contingent on someone else's opinion.

Is that an opinion I see?

 

[Bystander]

Is that an opinion I see?

"Not just ANY opinion, K-man's opinion."

 

[kuruman]

Is that an opinion I see?

"Not just ANY opinion, K-man's opinion."

You're both right!

 

[Orodruin]

You're both right!

That’s what I love about science, there’s no one right answer.