Finding Distance with Varying Force: A Homework Problem

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SUMMARY

The discussion focuses on calculating the distance traveled by an object under a time-varying force described by the equation F(t) = k * e^(-c*t), where k = 6.0 N and c = 0.10 (1/s). The object has a mass of 1.0 kg and an initial velocity of 2.0 m/s at the origin. To find the distance after 20 seconds, users are advised to apply Newton's second law in the form F = m * (dv/dt) to derive velocity as a function of time, followed by integrating to determine displacement.

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  • Understanding of Newton's second law of motion
  • Basic calculus for integration
  • Familiarity with exponential functions
  • Knowledge of kinematics equations
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  • Learn how to derive velocity from force using F = m * (dv/dt)
  • Study integration techniques for calculating displacement over time
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Students in physics, particularly those studying mechanics, as well as educators and anyone interested in understanding the effects of varying forces on motion.

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Homework Statement


An object of mass m=1.0kg experiences a force of the following mathematical form,

F(t)=k*e^(-c*t) i

where k=6.0N and c=0.10 (1/s) and i indicates the unit vector in the x-direction.At time t=0, the object has a velocity of v=2.0 m/s and is at the origin. Where is this object after 20 seconds?

Homework Equations


F=ma.. maybe..

The Attempt at a Solution


I used the force equation and F=ma to get the acceleration and was going to use the x=(vo)t +(1/2a)t^2 equation, but then I realized that doesn't make sense... I'm kind of confused though... How do you find the distance if the force varies? Thanks in advance.
 
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Once you've found the acceleration, as you say, use the most general form of the equations between acceleration, velocity and displacement to find the displacement for this case.

Dorothy
 
You should use the Newton's second law in this form

[tex]F = m\frac{dv}{dt}[/tex]

Then you find [tex]v[/tex] as a function of time [tex]t[/tex].

Remember that [tex]dx = vdt[/tex].

Calculate [tex]\int_0^{20}dx[/tex] to find the answer.
 

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