Finding eigenvectors and eigenspinors of S_y

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The discussion centers on calculating the eigenvectors and eigenvalues of the operator S_y, specifically in the context of quantum mechanics. The participants clarify that S_y can be expressed as S_y = (ħ/2)σ_y, where σ_y is a Pauli matrix. The eigenvalues of S_y are confirmed to be ħ/2 and -ħ/2, as S_y is a Hermitian operator, ensuring real eigenvalues. The conversation emphasizes the importance of understanding the relationship between eigenstates and eigenvalues, particularly in the context of measuring observables in quantum mechanics.

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  • Understanding of quantum mechanics principles, specifically spin-1/2 systems.
  • Familiarity with Pauli matrices, particularly σ_y.
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Wishbone
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I have a homework problem whose first part asks for the eigenvectors and eigenspinors of S_y. My problem is following the text to figure out what (mathematically) is S_y.
Also, The book first derives S^2, using the following method using 3/4\hbar^2 as the eigenvalue. I was orignally going to follow the books example for S^2 and use the same strategy, however since they didnt explain themselves, I am a little confused. Any help would be appreciated. Thanks.
 
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Presumably you are trying to calculate the eigenvectors of S_y in terms of the eigenvectors of S_z. The electron is spin half so the spin is represented by the Pauli matrices i.e. S_y = \frac{\hbar}{2} \sigma_y. Since you know the matrix representation of S_y in the S_z basis, what should you do to find the eigenvectors?
 
Ooops I ment to say eigenvalues, not eigenvectors. Sorry about that. I do not know of S_y expressed as a matrix in the S_z basis though. I know that

S_y= (\frac{1}{1i})(S_+ - S_-) if I substitue S_y = \frac{\hbar}{2} \sigma_y into that first equation, I get S_y = \frac {h}{2i}times the 2x2 matrix: first row (0,1) second row (-1,0).

so is \frac{\hbar}{2i} and -\frac{\hbar}{2i} my eignevalues?

sry not sure how to get matricies done with latex.
 
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Wishbone said:
Ooops I ment to say eigenvalues, not eigenvectors. Sorry about that. I do not know of S_y expressed as a matrix in the S_z basis though. I know that

S_y= (\frac{1}{1i})(S_+ - S_-) if I substitue S_y = \frac{\hbar}{2} \sigma_y into that first equation, I get S_y = \frac {h}{2i}times the 2x2 matrix: first row (0,1) second row (-1,0).

so is \frac{\hbar}{2i} and -\frac{\hbar}{2i} my eignevalues?

sry not sure how to get matricies done with latex.

Since S_y is an observable (Hermitian) its eigenvalues are ofcourse real, so it can't be the right answer.
BTW: I think the relation should be S_y=\frac{1}{2i}(S_+-S_-).

What do you know about S_+ and S_-? Do you know how they act on the eigenstates of S_z?
 
ah yes 1/2i sry bout that.Well I know S_+ and S_-, and knowing that S_y= (\frac{1}{2i})(S_+-S_-) we can simplify and get

S_z = \frac{\hbar}{2} \sigma_zbut I am not sure what to do with that, or what it means to the eigenvalues of S_y
 
So what happens if you let S_y act on |\frac{1}{2} \frac{1}{2}\rangle and |\frac{1}{2} -\frac{1}{2}\rangle?
 
It's not cheating but i think your problem's solved in Schaum's outline on Quantum Mechanics (solved problems book).

Daniel.
 
ah thanks guys for the hints, I think I got it. However, I did get trying to find the probibility of finding S_y in the general state of \chi. My general state \chi = a(\frac{1}{\sqrt{2}},\frac{i}{\sqrt{2}}) + b(\frac{1}{\sqrt{2}},\frac{-i}{\sqrt{2}}) where those row vectors are actually collum vectors. So obviously a,b are going to be my coefficents, but when I try to normalize this, I do not get 1/2 and 1/2 for my answer. I am not sure what I'm doing wrong! thanks in advance.
 
Ok, so you've found the right eigenstates of S_y and you've written some general state \chi as a linear combination of these eigenstates. Did you also find the corresponding eigenvalues? (That should be really easy now)

What do the postulates say about the probability of measuring, say \frac{\hbar}{2}, if you measure S_y for the state \chi?

BTW: You wrote: 'the probability of finding S_y. A hope that was a typo. You MEASURE an observable. You FIND an eigenvalue with some probability. The probability ofcourse depends on the state, so it's not always 1/2 and 1/2.
 
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  • #10
Yes that's what i ment, i guess i was trying to be a little too pithy. I think I know of the posulate you are thinking of,
\chi = (\frac{a + b}{\sqrt{2}})\chi_+ + (\frac{a - b}{\sqrt{2}})\chi_-
where \chi_+ coressponds to the eigenvaule \frac {\hbar}{2} and \chi_- coressponds to \frac {-\hbar}{2}
Oh wait, I forgot that when I find the probabilities, its |a+b|^2 and |a-b|^2

which in both cases means (a+b)(a-b^*)
 
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  • #11
Wishbone. I would advice you to read your book and go through each of the postulates carefully. I find it hard to understand what you mean exactly with most of the questions you post. This question is the simplest possible nontrivial exercise in applications of the QM postulates in the sense that the state space is simply 2-dimensional. But it seems as though the relationship between and importance of observable operators, eigenvectors and eigenvalues is not clear. Please read your book and come with questions if something is not clear. If you make exercises before understanding the fundamentals you will not learn much from them.
 
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  • #12
I am not exactly sure what you mean, this specific question was to find the probiblities. I read the book, I do not understand all of it, obviously, which is why I came here. What about my question is unclear?
 
  • #13
Wishbone said:
Yes that's what i ment, i guess i was trying to be a little too pithy. I think I know of the posulate you are thinking of,
\chi = (\frac{a + b}{\sqrt{2}})\chi_+ + (\frac{a - b}{\sqrt{2}})\chi_-
where \chi_+ coressponds to the eigenvaule \frac {\hbar}{2} and \chi_- coressponds to \frac {-\hbar}{2}



Oh wait, I forgot that when I find the probabilities, its |a+b|^2 and |a-b|^2

which in both cases means (a+b)(a-b^*)

This post is vague. I guess, but am not sure that \chi_+ and \chi_- are supposed to be the eigenstates of S_x. Then, if the general state in terms of the eigenfunctions of S_z is \chi=a\chi_{z_+}+b\chi_{z_-}, then the expansion \chi as a linear combination of the eigenstates of S_x is \chi = (\frac{a + b}{\sqrt{2}})\chi_+ + (\frac{a - b}{\sqrt{2}})\chi_-
as you wrote down.
Anyway I shouldn't have to guess this and it also doesn't immediately apply to your problem since you must have the eigenstates of S_y, not those of S_x.

Ok, here is a question to see if you got the postulates down right. Suppose \{|\varphi_n\rangle\}_{n=1}^{N} is a complete set of eigenstates of the observable Q with |\varphi_i\rangle corresponding to the eigenvalue a_i Assume the spectrum is nondegenerate. Let |\psi\rangle be an arbitrary ket and expand it in the given eigenbasis:

|\psi \rangle =\sum_{i=1}^N c_n |\varphi_n\rangle

Now, for a system in the state |\psi\rangle, what is the probability of measuring a_i when a measurement of Q is made?

If you can answer this, you can also answer the question on your problem.
 
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