Finding Electric Flux of a Disc of Radius r

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Homework Help Overview

The discussion revolves around calculating the electric flux due to a charged particle at a specific distance from a disc of radius r. Participants are exploring the relationship between electric flux and electric fields, particularly in the context of point charges and closed surfaces.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are questioning the appropriateness of using electric flux in this scenario, noting that flux is typically associated with closed surfaces. There are discussions about whether the focus should be on the electric field instead. Some participants are seeking clarification on the nature of the charge (point charge vs. ring) and the relevant surface for calculating flux.

Discussion Status

The discussion is active, with participants raising important questions about the definitions and assumptions related to electric flux and electric fields. There is a lack of consensus on the correct approach, but several participants are providing guidance on clarifying the problem setup.

Contextual Notes

Participants are navigating the complexities of applying Gauss's law and the distinction between electric flux and electric fields, particularly in relation to point charges and their respective surfaces. There is an emphasis on ensuring that the question is framed correctly to facilitate productive discussion.

prasum
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a disc of radius r we have to find electric flux at a point which is at a distance r from the centre



i have used e=(sigma/2eo)(1-x/sqrt(r^2+x^2)) the area da=2pir*dr

i know flux=closed integral (e.da)
and x=r

after that what should i do
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r from the center in which direction? Is it along the axis? also since flux is a closed integral, flux at any point does not make sense. Electric field will be more appropriate...
 
ashishsinghal said:
r from the center in which direction? Is it along the axis? also since flux is a closed integral, flux at any point does not make sense. Electric field will be more appropriate...

yes it is along axis
 
you haven't answered whole of my question. Is it really flux what you are talking about as flux is for a closed surface.
Also if it was flux then since it is just a point with no charge by gauss law, flux would be zero.
It has to be field.
 
ashishsinghal said:
you haven't answered whole of my question. Is it really flux what you are talking about as flux is for a closed surface.
Also if it was flux then since it is just a point with no charge by gauss law, flux would be zero.
It has to be field.

the point is a charged particle
 
prasum said:
the point is a charged particle

is it a ring or a point charge?
flux or field?
if flux .. what is the surface?

please correct your question and post again ...


@ Ashish

how was your JEE?
 
cupid.callin said:
is it a ring or a point charge?
flux or field?
if flux .. what is the surface?

please correct your question and post again ...


@ Ashish

how was your JEE?

it is point charge
 
prasum said:
it is point charge

and flux
 
so what is the surface?>?

flux is always for a surface

anyway if you are asking for flux due to point charge on a spherical surface of radius r and centerd at the charge then its \frac{q}{\epsilon_o}
 

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