Finding Electric Potential at P, Q and R in a Earthed Circuit

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Homework Help Overview

The discussion revolves around finding the electric potentials at points P, Q, and R in a circuit where point S is earthed. The context involves applying Kirchhoff's laws and understanding voltage drops across resistors in relation to the circuit's configuration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the direction of current flow and its implications for voltage calculations across resistors. Questions arise about the relationship between the potential at points P, Q, and R and the potential differences across the resistors.

Discussion Status

Some participants have provided guidance on using Ohm's law to calculate voltage drops and have encouraged further exploration of the problem. There is an acknowledgment of the need to consider the reference point for potential measurements, and attempts to clarify the connections between current flow and potential differences are ongoing.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use. The discussion reflects a mix of understanding and uncertainty regarding the application of circuit laws and the implications for potential at specific points.

thereddevils
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Homework Statement



In the circuit given (attached) , point S is earthed , what are the electrical potentials at point P , Q and R .

Homework Equations



Kirchoff's second law .

The Attempt at a Solution



The electric potential at point S is 0 . By applying Kirchoff's second law ,

I(2+3)=15-5

I=2A

i am not sure where to go from here .
 

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You found the current. In what direction does it flow? Use that to find the voltage drops across each resistor.
 
Doc Al said:
You found the current. In what direction does it flow? Use that to find the voltage drops across each resistor.

ok , the current is flowing in the clockwise direction . Could you elaborate a little further on the voltage calculation of each resistors ?

But the question is asking for the potential at points P,Q and R respectively . How is it related to the potential difference across the resistors .

Thanks !
 
thereddevils said:
ok , the current is flowing in the clockwise direction .
Good.
Could you elaborate a little further on the voltage calculation of each resistors ?
Sure. The voltage across each resistor is given by Ohm's law: ΔV = IR. To find the sign of the voltage across the resistor, you need to know the direction of the current. Hint: Does current across a resistor flow from lower to higher potential or from higher to lower?

But the question is asking for the potential at points P,Q and R respectively . How is it related to the potential difference across the resistors .
To find the potential at any point with respect to some reference, just add up the voltage drops across each piece. Here your reference is point S, which is marked as ground and thus is at 0 Volts. To find the potential of point P, for example, you need to find ΔV from S to P. S to P contains a battery, so what's ΔV? To find the potential of point Q, you'll add up the voltage drops across S-P and P-Q. What's the voltage drop from P to Q across that 2 Ω resistor?
 
Doc Al said:
Good.

Sure. The voltage across each resistor is given by Ohm's law: ΔV = IR. To find the sign of the voltage across the resistor, you need to know the direction of the current. Hint: Does current across a resistor flow from lower to higher potential or from higher to lower?


To find the potential at any point with respect to some reference, just add up the voltage drops across each piece. Here your reference is point S, which is marked as ground and thus is at 0 Volts. To find the potential of point P, for example, you need to find ΔV from S to P. S to P contains a battery, so what's ΔV? To find the potential of point Q, you'll add up the voltage drops across S-P and P-Q. What's the voltage drop from P to Q across that 2 Ω resistor?

thanks ! Now , i understand this question better . Let me attempt again .

Since the emf of the 15 V battery > emf of 5V battery , the current will be flowing in the clockwise direction .

pd across sp would simply be -5V .

pd across 2 ohm resistor is 2/(2+3) x (5-15)=-4V so pd across SQ is -5-4=-9V

pd across 3 ohm resistor is 3/(2+3) x (5-15)=-6V so pd across SR is -15 V

Are my reasonings correct ?
 
Perfecto!

Just for fun, realize that you can find the potential of a point (Q, say) by starting from S and going clockwise around the circuit or by going counter-clockwise. Do it both ways and check that you get the same answer.
 
Doc Al said:
Perfecto!

Just for fun, realize that you can find the potential of a point (Q, say) by starting from S and going clockwise around the circuit or by going counter-clockwise. Do it both ways and check that you get the same answer.

yay! Thanks ! Yeah , i have experimented with that
 

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