Chemistry Finding equilibrium expression for an equilibrium equation

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SUMMARY

The discussion centers on formulating an equilibrium expression for a reaction involving only liquids. It is established that solids and pure liquids are excluded from the equilibrium constant expression due to their activities being equal to 1. Participants emphasize the importance of converting reactant masses to moles using molar masses to determine initial concentrations. The confusion arises from the typical focus on gaseous and aqueous species, but in this case, the reactants are treated as aqueous due to their dissolution in a solvent.

PREREQUISITES
  • Understanding of equilibrium constants and expressions
  • Knowledge of molar mass calculations
  • Familiarity with the concept of activities in chemical reactions
  • Basic principles of solution chemistry, particularly regarding aqueous solutions
NEXT STEPS
  • Study the derivation of equilibrium constant expressions for various states of matter
  • Learn about the role of activities in equilibrium calculations
  • Explore the differences between aqueous and non-aqueous solutions in chemical reactions
  • Review examples of equilibrium problems involving liquids and their expressions
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical equilibrium studies, particularly those focusing on liquid-phase reactions and solution chemistry.

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Reaction score
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Homework Statement
Write the equilibrium expression for this reaction
Relevant Equations
Kc=(product A)×(product B)
----------------------------------------
(Reactant A)×(Reactant B)
In the d(i) part, we are asked to write an equilibrium constant. It was mentioned in the chapter that solids and liquids will not be added in the equation. So, I think that there is not going to be any Expression for this reaction as all the reactants and products are liquids. Is my answer right?
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Solids and immiscible liquids.
 
I suggest you use square brackets in your above expressions to remind yourself that you are dealing with molarities.
 
You need to convert the masses of your reactants into moles using their respective molar masses. You can then find the initial concentrations from the moles and the given volume. The reactions shows the reactants as liquids but they are being dissolved in a solvent which then makes them aqueous. You need the values for part (a) in order to complete the entire problem.
 
There's always an expression. The reason we don't include materials with certain properties is because their activities evaluate to 1, i.e. something multiplied by 1 is itself, so it's not written out. The confusion likely arises from the fact that we usually only include (g) and (aq) samples in these equations, since a lot of problems are concerned with dissolved gases, salts or acid/bases. However, this problem deals with a mixture of liquids rather than what we would usually consider a solution (i.e. something solid or gaseous dissolved).
 

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