Relationship between chemical equilibrium and rate equilibrium

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r12214001
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Homework Statement
equilibrium
Relevant Equations
equilibrium
Q: Is it true that the value of K depends on the amounts of reactants and products mixed together initially? Explain.

A:NO, Equilibrium and rates of reaction (kinetics) are independent of each other. A reaction with a large equilibrium constant value may be a fast reaction or a slow reaction. The same is true for a reaction with a small equilibrium constant value.

why the solution manual state that independent of each other?
In my opinion that rate constant of K(forward)/K(reverse)=K(equilibrium constant). Regarding this equation, we can get that K(equilibrium constant) is related to rate constant of K .it is not independent !
 
on Phys.org
You haven't quoted the question or the solution manual very completely but pretty surely you have not answered the question which asks nothing about rates.
 
r12214001 said:
In my opinion that rate constant of K(forward)/K(reverse)=K(equilibrium constant). Regarding this equation, we can get that K(equilibrium constant) is related to rate constant of K .it is not independent !

It depends on what you mean by "independent". In the kinetic approach to equilibrium you can say K depends on the kf/kr ratio, but it is not the same thing as each k separately. Especially taking into account fact you can't change one of ks without changing the other at the same time.