Finding Equilibrium Forces in a Two-Member Frame

  • Thread starter Thread starter rico22
  • Start date Start date
  • Tags Tags
    Frame Statics
Click For Summary
SUMMARY

The discussion focuses on solving equilibrium forces in a two-member frame subjected to a 200-lb cylinder and a 500 lb-ft couple moment. The user initially calculated the forces on members AC and CB but encountered discrepancies in the vertical force at point A, which should be 175 lbs instead of the calculated 200 lbs. Key insights include the necessity of incorporating the couple moment and the roller support reaction in the free body diagram (FBD) for accurate calculations. The final resolution emphasizes the importance of summing external forces and moments correctly.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of free body diagrams (FBD)
  • Familiarity with force summation equations (ƩFx and ƩFy)
  • Concept of couple moments in structural analysis
NEXT STEPS
  • Study the application of free body diagrams in structural mechanics
  • Learn about the effects of roller and pin supports in two-dimensional frames
  • Explore the calculation of moments in static equilibrium problems
  • Review examples of equilibrium analysis involving multiple forces and moments
USEFUL FOR

Engineering students, structural analysts, and anyone involved in mechanics or statics who seeks to understand equilibrium forces in two-member frames.

rico22
Messages
51
Reaction score
0

Homework Statement



The two-member frame (see picture attached) supports the 200-lb cylinder and 500
lb–ft couple moment. Determine the force of the roller at B on member
AC and the horizontal and vertical components of force which the pin at
C exerts on member CB and the pin at A exerts on member AC. The
roller C does not contact member CB.


Homework Equations





The Attempt at a Solution


I split the frame into members AC and CB. The I found the forces acting on D(pulley) which gave me Dx = 200 lb and Dy = 200 lb. I plugged this into member CB; giving me the next equations:
ƩFx = 0: Cx +Bx -200 = 0
∴ Cx + Bx = 200

ƩFy = 0: Cy - 200 = 0
∴ Cy = 200

ƩMc = 0: 200(4) - 4Bx = 0
∴ Bx = 200 which also give me Cx = 0 from the summation of Forces in the x direction.
Then I plug the relevant values of Cx, Cy and Bx into the AC member; this gives me the following equations:
ƩFx = 0: Ax - Bx + 200(from cable) = 0
∴ Ax = 0

ƩFy = 0: Ay - 200 = 0
∴ Ay = 200
The issue that I am having is that this last answer is wrong according to the book. Its supposed to be Ay = 175 lbs. I know I didn't use the couple moment at all so, maybe this is the reason? But I really don't see how it could be 175 lbs. Any help would be greatly appreciated.
 

Attachments

  • two member frame.PNG
    two member frame.PNG
    16.5 KB · Views: 1,258
Physics news on Phys.org
rico22 said:

Homework Statement



The two-member frame (see picture attached) supports the 200-lb cylinder and 500
lb–ft couple moment. Determine the force of the roller at B on member
AC and the horizontal and vertical components of force which the pin at
C exerts on member CB and the pin at A exerts on member AC. The
roller C does not contact member CB.


Homework Equations





The Attempt at a Solution


I split the frame into members AC and CB. The I found the forces acting on D(pulley) which gave me Dx = 200 lb and Dy = 200 lb.
this is ok
I plugged this into member CB; giving me the next equations:
ƩFx = 0: Cx +Bx -200 = 0
∴ Cx + Bx = 200

ƩFy = 0: Cy - 200 = 0
∴ Cy = 200
No you cannot just isolate CB without including the pulley forces and torque.
The issue that I am having is that this last answer is wrong according to the book. Its supposed to be Ay = 175 lbs. I know I didn't use the couple moment at all so, maybe this is the reason?
well it has to factor in somewhere, right?
But I really don't see how it could be 175 lbs.
It is.
Any help would be greatly appreciated.
Before pulling the frame apart, try summing external forces = 0 and summing moments of external forces about A = 0. Only the cylinder weight and couple and reactions at A and C are external to the system.
 
Thank you for the reply. So if I take the entire frame would C then become a roller and not a pin?
 
ok I got it now... I was supposed to plug in the roller support reaction into the FBD of AC on top of Cy and Cx...that was throwing the whole thing off... thanks again.
 
You are missing the normal reaction because of the roller.
Link to the solution.
https://faculty.uca.edu/njaustin/ENGR2311/Quizzes/quiz07.pdf

Good job guyz. Enjoy.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
8K