Finding Equilibrium Forces in a Two-Member Frame

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Homework Help Overview

The problem involves analyzing a two-member frame that supports a 200-lb cylinder and a 500 lb-ft couple moment. Participants are tasked with determining the forces exerted by various supports on the frame members.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss splitting the frame into its members and analyzing forces acting on them. There are attempts to apply equilibrium equations for both horizontal and vertical forces, as well as moments. Some participants question the omission of the couple moment in their calculations, while others suggest that the roller support's reaction needs to be included in the free body diagram.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved. Some guidance has been offered regarding the importance of including all external forces and moments in the analysis. There is recognition of the need to reconsider the role of the roller support in the calculations.

Contextual Notes

Participants note that the roller does not contact one of the members, which may affect the analysis. There is also mention of potential discrepancies between calculated values and those provided in reference materials.

rico22
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Homework Statement



The two-member frame (see picture attached) supports the 200-lb cylinder and 500
lb–ft couple moment. Determine the force of the roller at B on member
AC and the horizontal and vertical components of force which the pin at
C exerts on member CB and the pin at A exerts on member AC. The
roller C does not contact member CB.


Homework Equations





The Attempt at a Solution


I split the frame into members AC and CB. The I found the forces acting on D(pulley) which gave me Dx = 200 lb and Dy = 200 lb. I plugged this into member CB; giving me the next equations:
ƩFx = 0: Cx +Bx -200 = 0
∴ Cx + Bx = 200

ƩFy = 0: Cy - 200 = 0
∴ Cy = 200

ƩMc = 0: 200(4) - 4Bx = 0
∴ Bx = 200 which also give me Cx = 0 from the summation of Forces in the x direction.
Then I plug the relevant values of Cx, Cy and Bx into the AC member; this gives me the following equations:
ƩFx = 0: Ax - Bx + 200(from cable) = 0
∴ Ax = 0

ƩFy = 0: Ay - 200 = 0
∴ Ay = 200
The issue that I am having is that this last answer is wrong according to the book. Its supposed to be Ay = 175 lbs. I know I didn't use the couple moment at all so, maybe this is the reason? But I really don't see how it could be 175 lbs. Any help would be greatly appreciated.
 

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rico22 said:

Homework Statement



The two-member frame (see picture attached) supports the 200-lb cylinder and 500
lb–ft couple moment. Determine the force of the roller at B on member
AC and the horizontal and vertical components of force which the pin at
C exerts on member CB and the pin at A exerts on member AC. The
roller C does not contact member CB.


Homework Equations





The Attempt at a Solution


I split the frame into members AC and CB. The I found the forces acting on D(pulley) which gave me Dx = 200 lb and Dy = 200 lb.
this is ok
I plugged this into member CB; giving me the next equations:
ƩFx = 0: Cx +Bx -200 = 0
∴ Cx + Bx = 200

ƩFy = 0: Cy - 200 = 0
∴ Cy = 200
No you cannot just isolate CB without including the pulley forces and torque.
The issue that I am having is that this last answer is wrong according to the book. Its supposed to be Ay = 175 lbs. I know I didn't use the couple moment at all so, maybe this is the reason?
well it has to factor in somewhere, right?
But I really don't see how it could be 175 lbs.
It is.
Any help would be greatly appreciated.
Before pulling the frame apart, try summing external forces = 0 and summing moments of external forces about A = 0. Only the cylinder weight and couple and reactions at A and C are external to the system.
 
Thank you for the reply. So if I take the entire frame would C then become a roller and not a pin?
 
ok I got it now... I was supposed to plug in the roller support reaction into the FBD of AC on top of Cy and Cx...that was throwing the whole thing off... thanks again.
 
You are missing the normal reaction because of the roller.
Link to the solution.
https://faculty.uca.edu/njaustin/ENGR2311/Quizzes/quiz07.pdf

Good job guyz. Enjoy.
 

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