Finding equivalent impedance in parallel RC and RL circuit

[pokie_panda]

Homework Statement

http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/

Homework Equations

Vc=Vsource*Zeq/(200+Zeq)

The Attempt at a Solution

Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which is -j100
so we use the formula Z1 + Z2//Z3
which we get 400

Is this correct
Also how do we multiply the Vsource value ?

 

[gneill]

Homework Statement

[PLAIN]http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/
http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/

Homework Equations

Vc=Vsource*Zeq/(200+Zeq)

The Attempt at a Solution

Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which is -j100 $\leftarrow$ should be -j200?
so we use the formula Z1 + Z2//Z3
which we get 400

Is this correct

Your description is a bit hard to follow, but it looks like you've got the right procedure. Your result has the correct magnitude, but lacks the appropriate units (that would lose you marks if submitted that way!).

Also how do we multiply the Vsource value ?

Multiply the Vsource? For what purpose?

 

[pokie_panda]

I ended up getting the correct solution , thanks for your help