- #1

- 3

- 0

## Homework Statement

If R1 = 2 Ω, X1 = 1 Ω, R2 = 2 Ω, and X2 = -2 Ω , the equivalent impedance Zeq (in ohms) at terminals a and b is:

(the circuit diagram is attached to this post)

a. 3 + j 0

b. 3 + j 2

c. 3 - j 2

d. 0 - j 2

e. 0 + j 2

The answer is a. I have no idea how to get the answer. I have tried to simplify the circuit but I do not think I am doing it right.

## Homework Equations

Series: Zeq = Z1 + Z2

Parallel: Zeq = (Z1*Z2)/(Z1 + Z2)

Total Impedance is Z= r +jX

Zc = -jXc

ZL = j(XL)

## The Attempt at a Solution

I tried to:

1. combine R2 and and the capacitor in parallel (i think my errors occur here) i got (2+j) + (-4j/(2-2j))

2. combine R1 and the inductor in series (i got 2 +j1)

3. combine the rest in series.