Find the equivalent impedance of an infinite series of resistors and capacitors

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Homework Help Overview

The discussion revolves around finding the equivalent impedance of an infinite series of resistors and capacitors. Participants are exploring the implications of an infinite network and the relationships between series and parallel configurations of resistors and capacitors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to analyze the equivalent impedance by first considering a finite number of elements and then extrapolating to the infinite case. Questions arise about the definitions and roles of specific components, such as the variable 'B'. Some participants suggest considering the addition of unit cells to simplify the analysis.

Discussion Status

The discussion is ongoing, with participants providing insights and corrections to each other's posts. Some guidance has been offered regarding the approach to take when dealing with the infinite series, particularly the concept of treating the network as already infinite when adding new components.

Contextual Notes

There are mentions of potential confusion regarding component labels and the need for clarity in definitions. The participants are also navigating the complexities of deriving relationships between the impedances of the components involved.

kryzlof
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Homework Statement


Find the equivalent impedance of the infinite series of resistors and capacitors as shown below


-R----R----R----R----...R----...
____C____C____C____B_______C
-r----r----r----r----...r----...

Homework Equations


2.1. Equivalent resistance of resistors in series : R = R1 + R2 + R3 + ..
2.2. Equivalent resistance of resistors in parallel: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 +...
2.3. Equivalent capacitance of capacitors in series : 1 / C = 1 / C1 + 1 / C2 + 1 / C3 ...
2.4. Equivalent capacitance of capacitors in parallel: C = C1 + C2 + C3 +...

The Attempt at a Solution


I am trying to find the equivalent impedance of the first three elements first (R, r and B) and the for the six first... This should then converge, hopefully...
 
Last edited:
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kryzlof said:

Homework Statement


Find the equivalent impedance of the infinite series of resistors and capacitors as shown below


-R----R----R----R----...R----...
____B____B____B____B_______B
-r----r----r----r----...r----...

Homework Equations


2.1. Equivalent resistance of resistors in series : R = R1 + R2 + R3 + ..
2.2. Equivalent resistance of resistors in parallel: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 +...

The Attempt at a Solution


I am trying to find the equivalent impedance of the first three elements first (R, r and B) and the for the six first... This should then converge, hopefully...

What is B ?
 
Is this what you're going for?
attachment.php?attachmentid=47769&stc=1&d=1338323550.gif
 

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Yes, it is. Sorry for my misstake (it should be C, not B), I will correct my first post.
 
Rather than try to ferret out a converging series from increasingly complicated terms, consider what happens when you add one more "unit cell" at the front of an already infinite train of identical "cells" :wink:
 
kryzlof said:

Homework Statement


Find the equivalent impedance of the infinite series of resistors and capacitors as shown below


-R----R----R----R----...R----...
____C____C____C____B_______C
-r----r----r----r----...r----...

Homework Equations


2.1. Equivalent resistance of resistors in series : R = R1 + R2 + R3 + ..
2.2. Equivalent resistance of resistors in parallel: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 +...
2.3. Equivalent capacitance of capacitors in series : 1 / C = 1 / C1 + 1 / C2 + 1 / C3 ...
2.4. Equivalent capacitance of capacitors in parallel: C = C1 + C2 + C3 +...

The Attempt at a Solution


I am trying to find the equivalent impedance of the first three elements first (R, r and B) and the for the six first... This should then converge, hopefully...


The "trick" to most of these problems is to imagine that the network is already infinitely extensive to the right. Adding one more identical unit of impedance to the left of the network will not change the overall impedance.

If you let the impedance of the network be the unknown Z, you should be able to derive a quadratic equation with complex coefficients that Z satisfies.
 

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