Two-terminal components and electrical networks can be connected in series or parallel. The resulting electrical network will have two terminals, and itself can participate in a series or parallel topology. Whether a two-terminal "object" is an electrical component (e.g. a resistor) or an electrical network (e.g. resistors in series) is a matter of perspective. This article will use "component" to refer to a two-terminal "object" that participate in the series/parallel networks.
Components connected in series are connected along a single "electrical path", and each component has the same current through it, equal to the current through the network. The voltage across the network is equal to the sum of the voltages across each component. Components connected in parallel are connected along multiple paths, and each component has the same voltage across it, equal to the voltage across the network. The current through the network is equal to the sum of the currents through each component.
The two preceding statements are equivalent, except for exchanging the role of voltage and current.
A circuit composed solely of components connected in series is known as a series circuit; likewise, one connected completely in parallel is known as a parallel circuit. Many circuits can be analyzed as combination of series and parallel circuits, along with other configurations.
In a series circuit, the current that flows through each of the components is the same, and the voltage across the circuit is the sum of the individual voltage drops across each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component.Consider a very simple circuit consisting of four light bulbs and a 12-volt automotive battery. If a wire joins the battery to one bulb, to the next bulb, to the next bulb, to the next bulb, then back to the battery in one continuous loop, the bulbs are said to be in series. If each bulb is wired to the battery in a separate loop, the bulbs are said to be in parallel. If the four light bulbs are connected in series, the same current flows through all of them and the voltage drop is 3-volts across each bulb, which may not be sufficient to make them glow. If the light bulbs are connected in parallel, the currents through the light bulbs combine to form the current in the battery, while the voltage drop is 12-volts across each bulb and they all glow.
In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken. In parallel circuits, each light bulb has its own circuit, so all but one light could be burned out, and the last one will still function.
Summary:: Trying to find Rth but I do not get the same value as the one from the solution.
[moderator: moved from a technical forum. No template.]
I am trying to find Rth to solve this problem, however once I simplified it, I get a value of 700.745 Ω while in the solution, the answer is...
I apologize using English fluently because I am not an Enlgish speaker.
When I tried to solve this problem, I used current divider rule.
So, $$i_o(t) = \frac{3}{3+5}*4e^{-2t} = 1.5*e^{-2t} A$$
However, This was wrong.
The answer is $$ 1.5*e^{-2t} + 0.5 A$$
If I use $$V_O = L*\frac{di}{dt}$$...
Homework Statement
In the circuit diagram shown , Xc = 100 ohm , XL = 200 ohm , R = 100 ohm , the effective current through the source is ?
Homework Equations
Z= √( R^2 + ( XL - Xc)^2)
Vrms = Irms/ Z
The Attempt at a Solution
I tried to draw the phaser diagram and calculate the relation...
I've seen answers saying that electricity takes path of least resistance, I know this and there is no need to explain this for me.
A forum's answer told me that the electrons initially flow through to the path with resistance and eventually becomes congested (redirecting the remaining electrons...
Homework Statement
Homework Equations
The Attempt at a Solution
When we will move the contact X towards P, the potential difference should be maximum across the potential divider. I work out A as my answer but I think it is wrong.
Homework Statement
I'm asked to find a combination of resistors (parallel and/or series) that uses resistors of 25 Ω, 100 Ω, 50 Ω, and 50 Ω. They should add up to give a total resistance of 62.5 Ω.
Homework Equations
Req for parallel = 1/R1 + 1/R2 + ...
Req for series = R1 + R2 + ...
The...
Homework Statement
https://pasteboard.co/Hj3g5Km.jpg
When both switches 1 and 2 are closed,what is the total resistance of the set up? I couldn't figure out which resistors are connected in parallel and which resistors are actually in series in this set up when both swtiches are closed. I...
A circuit contains a 7.5V d.c power supply and three resistors. The total resistance of the circuit is 30 ohms. Why will the largest current in the 18 ohm resistor? As far as I know is that the smallest current will be in 60 ohm resistor because it has the maximum resistance. Please explain...
Homework Statement
https://imgur.com/3H3pCkD
R is the resistance of each resistor, determine total resistance in the circuit. (see the image in the link above)
Homework Equations
R=1/R₁+1/R₂+1/R₃+... (in parralel circuit)
R=R₁+R₂+R₃... (in series circuit)
The Attempt at a Solution
I'm...
I'm having a little trouble understanding capacitors in parallel and series.
I understand that if there are two capacitors in a circuit with a potential difference Vab then the potential difference across the capacitors is also Vab.
Every example I have seen have been for two capacitors with...
Homework Statement
Homework Equations
I = VR
Series = current the same, voltage different
Parallel = current different, voltage the same
The Attempt at a Solution
Is the 1 ohm and 15 ohm parallel? I'm still learning to differentiate it.
If yes, then R = 15/16 ohm
Is the R series to 5ohm? If...
Homework Statement
Reduction from top network to bottom network in the screen shot. I can not find the steps that have been taken to do this.
Fault impedance = Zfa = Zfb = Zfc = j0.5
Homework Equations
The Attempt at a Solution
in hand written screenshot, sorry for the mess, just to show...
[Note: Thread has been moved to the homework forums by a mentor]
This is the Given problem
This is my solution part 1
- What I did here is I series the R3 and R4 (R3 + R4), and I parallel the R34 to R5 (most of the calculation are from the calculator)
This is my solution part 2
The...
(sorry, I couldn't figure out how to insert an image from my drive) I have a problem where in finding the thevenin resistance I take out my independent sources and as a result I'm left with a resistor parallel to a short circuit. Should I ignore this resistor when calculating equivalent...
Homework Statement
L is a perfect inductor with inductance L. The switch is turned on at t=0 and the currents i1 and i2 run trhough the circuit as indicated by the figure.
Homework Equations
Given this circuit I need to find i1 and i2 for t=0 and t => infinity.
The Attempt at a Solution
For...
I have a ton of 1A buck converters, and have a 5A application in which i need to run. I do not want to order any new buck converters, because I already have so many 1A ones, and do not have money for any new ones. Each one can only handle 1A before it over heats.
I was wondering if I could use...
Homework Statement
What is the potential difference across each resistor?
I know that I'll have to incorporate the V=iR equation
but I don't know where to start though...
My first attempt was with these:
R1=4 R2=8 R3=5 R4=6 R5=3
24-I1R1-I1R2-I3R3+I4R4+I5R5=0
but this lead me nowhere so I...
Homework Statement
[/B]
What is the current between points A and B?
The current I is unknown.
The voltage is 12V.
R1 = 3 Ohm
R2 = 6 Ohm
R3 = R4 = 4 Ohm
Homework Equations
U= R*I
The Attempt at a Solution
Total resistance from both branches:
1/R = 1/(R_1+R_3) + 1/(R_2+R_4)
1/R = 1/7 +...
Homework Statement
Hello, can you help with this problem.
For the next circuit, determine the voltages
Homework Equations
I=V/RT
RT=R1+R2+R3+...+Rn
P=V^2/R
V=V1=V2=V3
I=V/R
GT=1/R1+1/R2+1/R3+...+1/Rn
The Attempt at a Solution
My background is that I only know a very few and I don´t know how to...
Homework Statement
Solve the next circuit to find the voltages
Homework Equations
I=V/R
GT=(1/R1)+(1/Rn)
V=V1=V2=V3
The Attempt at a Solution
My background is that I know that in a parallel circuit, the voltage for each component is the same and electric current it's equal to the sum of the...