Finding equivalent resistance in a circuit diagram

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Hello
I am new to the forum as well as a new EE student. Can't figure it out this particular diagram in terms of how to find an equivalent resistance. Any kind help would be very very appreciated.
Thanks in advance. Please see attached.
Bila
 

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masum79 said:
Hello
I am new to the forum as well as a new EE student. Can't figure it out this particular diagram in terms of how to find an equivalent resistance. Any kind help would be very very appreciated.
Thanks in advance. Please see attached.
Bila
Hello masum79. Welcome to PF !

This thread has been moved to the Engineering Homework section.

Before we can help with homework, you must show some effort towards a solution.

Hint: No current flows across the gap marked v0 .

[ IMG]https://www.physicsforums.com/attachment.php?attachmentid=59042&d=1369634684[/PLAIN]
 
Dear SammyS, Thank you for the lead.
I figure it out since there is not current going through. So, I found Vo to be +2.0V. But my friend said it would be -2.0V. That one I am not sure why It would be minus instead of plus.--Bila
 
masum79 said:
I figure it out since there is not current going through. So, I found Vo to be +2.0V. But my friend said it would be -2.0V. That one I am not sure why It would be minus instead of plus.
How did you get +2V?
 
masum79 said:
Dear SammyS, Thank you for the lead.
I figure it out since there is not current going through. So, I found Vo to be +2.0V. But my friend said it would be -2.0V. That one I am not sure why It would be minus instead of plus.

--Bila
What is the voltage drop across (either) 300 Ω resistor?

What is the voltage drop across (either) 200 Ω resistor?
 
There is only one 200Ω resistor.

The magnitude of the voltage difference is indeed 2V. The question now is the polarity.

The circuit diagram tells you which side is +ve _if_ Vo is a positive number. The OP needs to work out which side actually is more positive than the other.
 
CWatters said:
There is only one 200Ω resistor.
DUH !

I've got to proof my posts better !


Too much cut & paste .