Finding Equivalent Resistance in a Combination Circuit

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The discussion revolves around calculating the equivalent resistance in a combination circuit of identical resistors between points a and b. Participants clarify the formulas for series and parallel resistances, emphasizing that the correct equations are Req = R1 + R2 + R3 for series and Req = (1/R1 + 1/R2 + 1/R3)^-1 for parallel configurations. There is confusion regarding the terms R1 and R3 in relation to R, and participants suggest simplifying the equation based on the circuit diagram. One participant mentions a friend's solution of 2 + (3)^-1, prompting further inquiry into the relationships between the resistors. The discussion highlights the need for clarity in expressing resistor values and their configurations in the circuit.
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Homework Statement


What is the equivalent resistance of the combination of identical resistors between points a and b in the figure below?

Homework Equations


Series= Req= R1 + R2 + R3 etc
Parallel = Req= (1/R1 + 1/R2 + 1/R3 etc)^-1

The Attempt at a Solution


Req= R1 + (1/3R) + R3

I don't know what to do from here.
 

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Parallel= Req= R1 + R2 + R3 etc
Series= Req= (1/R1 + 1/R2 + 1/R3 etc)^-1

These equations are wrong. The correct ones are
series= Req= R1 + R2 + R3 etc
Parallel = Req= (1/R1 + 1/R2 + 1/R3 etc)^-1
 
Thank you is this correct I only have one more submission
 
Req= R1 + (1/3R) + R3
Check the second term in the equation.
 
I tried that answer already and it says "Check the syntax of your response".
 
rl.bhat said:
Req= R1 + (1/3R) + R3
Check the second term in the equation.

The second term is right if he means 1/3 R and not 1/(3R). However, what is R1 and R3 in terms of R? Can you simplify the equation?
 
There are no numerical values for R. I asked my friend and the correct answer is 2 + (3)^-1.

Not sure how she got it.
 
I know there are no numerical values for R, which is why I asked how R1 and R3 relate to R. Look at the diagram and figure out what R1 and R3 are in terms of R.
 

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