Finding f(x) Given f''(x) and f'(x)

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SUMMARY

The discussion focuses on finding the function f(x) given its second derivative f''(x) = SQRT(x) - 2 cos(x). The user successfully derived the first derivative as f'(x) = (2/3)x^(3/2) - 2 sin(x) + C and the function f(x) as f(x) = (4/15)x^(5/2) + 2 cos(x) + C + D. A critical point raised was the treatment of the constant C during the second integration, suggesting it should be represented as Cx to account for the variable nature of integration constants.

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Homework Statement



f''(x) = SQRT(x) - 2 cos(x)

What is f(x)? (all possible solutions)

Homework Equations



-

The Attempt at a Solution



Well here is what i got:

f'(x) = (2/3)x^(3/2) - 2 sin(x) + C
f(x) = (2/3)(2/5)x^(5/2) + 2 cos(x) + C + D

thus final answer is:

f(x) = (4/15)x^(5/2) + 2 cos(x) + C + D

I hope that's right!

Thanks for your time! :)
 
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It's correct except for one thing. When you integrate the second time, you're integrating a constant C. What should C have after the second integration?
 
Cx ?

o you thank you!
 

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