Finding Final temp for Adiabatic process

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Discussion Overview

The discussion revolves around calculating the final temperature of air in a bicycle tire after a reversible adiabatic compression. Participants explore the relationships between pressure, volume, and temperature in the context of thermodynamics, specifically focusing on the equations relevant to adiabatic processes.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses confusion about starting the problem, noting a lack of information such as the number of moles or volume, which complicates the use of ideal gas laws.
  • Another participant proposes a relationship between temperatures and volumes, suggesting that (Tf/Ti)^c = Vi/Vf and (Pf/Vf)^(1/gamma) = ViVf could be combined, questioning the legitimacy of this approach.
  • A later reply points out typos in the proposed equations and encourages a clearer rewrite.
  • Another participant suggests expressing the adiabatic condition in terms of temperature and pressure, hinting at the need to consider the air in the tire as a compression of a larger volume of air at atmospheric pressure.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to solve the problem, and multiple competing views and methods are presented without resolution.

Contextual Notes

Participants note missing information and unresolved variables, such as the number of moles and volume, which affect the ability to apply the ideal gas law directly. The discussion also highlights the complexity of relating different thermodynamic variables in an adiabatic process.

speny83
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Homework Statement



A nearly flat bicycle tire becomes noticeably warmer after it has been pumped up. Approximate this process as a reversible adiabatic compression. Assume the initial pressure and temperature of the air before it is put in the tire to be Pi = 1.00 bar and Tf 287K . The final pressure in the tire is Pf = 3.75 bar.

Calculate the final temperature of the air in the tire. Assume that CV,m = 5R/2.

Homework Equations


dU=nCvmdt
dU=dw...as q=0 adiabaitc
dw=-Pexdv
using these above equations my notes derive the following
ViTic=VfTfc where c=Cvm/R
PiVi\gamma=PfVf\gamma where gamma=Cpm/Cvm

The Attempt at a Solution



I am really stuck on where to even start this problem. It seems as if i am missing info, that i need a number of moles or a volume or something. I can't seem to find a way to rearange any of the above. In other problems it boiled down to using the boring old ideal gas pv=nrt to solve for one variable but again this leaves me with 2 unknows so I am not sure what to do.

Any tips, hints, explanations anything would be a great help!\gamma
 
Last edited:
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can i say that So I am thinking can i say that
(Tf/Ti)^c=Vi/Vf and (Pf/Vf)^(1/gamma)=ViVf

so that (Tf/Ti)^c=(Pf/Vf)^(1/gamma)


is this legit?
 
speny83 said:
can i say that So I am thinking can i say that
(Tf/Ti)^c=Vi/Vf and (Pf/Vf)^(1/gamma)=ViVf

so that (Tf/Ti)^c=(Pf/Vf)^(1/gamma)


is this legit?
You have a couple of typos in there. Rewrite it more carefully.
 
speny83 said:

Homework Statement



A nearly flat bicycle tire becomes noticeably warmer after it has been pumped up. Approximate this process as a reversible adiabatic compression. Assume the initial pressure and temperature of the air before it is put in the tire to be Pi = 1.00 bar and Tf 287K . The final pressure in the tire is Pf = 3.75 bar.

Calculate the final temperature of the air in the tire. Assume that CV,m = 5R/2.

Homework Equations


dU=nCvmdt
dU=dw...as q=0 adiabaitc
dw=-Pexdv
using these above equations my notes derive the following
ViTic=VfTfc where c=Cvm/R
PiVi\gamma=PfVf\gamma where gamma=Cpm/Cvm

The Attempt at a Solution



I am really stuck on where to even start this problem. It seems as if i am missing info, that i need a number of moles or a volume or something. I can't seem to find a way to rearange any of the above. In other problems it boiled down to using the boring old ideal gas pv=nrt to solve for one variable but again this leaves me with 2 unknows so I am not sure what to do.

Any tips, hints, explanations anything would be a great help!\gamma
Try expressing the adiabatic condition in terms of T and P. Think of the air in the tire at the end as a compression of a much greater volume of air at atmospheric pressure into the final volume of the tire.

AM
 

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