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Finding force and equation of motion

  1. Dec 6, 2014 #1
    1. The problem statement, all variables and given/known data
    If v(x)=ax-2, then what is its force in terms of x. What is its motion as a function of time when x=a?

    2. Relevant equations


    3. The attempt at a solution
     
  2. jcsd
  3. Dec 6, 2014 #2

    ehild

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    What is v(x)? The motion of what are you speaking about?
    Show the relevant equations and your attempt to solve the problem.
     
  4. Dec 6, 2014 #3
    It is the motion along a horizontal frictionless plane. I did F=m dv/dt= m dv/dx*dx/dt= -2ma2x-5
    Then I fould potential energy by integration. However I could not find the motion of the particle.
     
  5. Dec 6, 2014 #4

    ehild

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    How do you specify the motion of a particle at a given time or at a given place? You give the velocity and acceleration. What are they at x=a?
     
  6. Dec 6, 2014 #5
    Sorry for the incomplete question.
    If the particle starts at the position x = a, find its motion as a function of time.
     
  7. Dec 7, 2014 #6

    ehild

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    You know that v=dx/dt. You have the equation dx/dt=ax-2 This is a very simple separable differential equation. Can you solve?
     
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