Finding Force Values Using Pythagorean Theorem

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When calculating force values, if one component is zero, such as f1x=0 and f1y=5, the net force equals the non-zero component, which is 5. The Pythagorean Theorem is only applicable when both components are non-zero, forming a right triangle. In this case, since there is no x component, the force f1 is simply equal to f1y, which is 5. Thus, the calculation simplifies to f1 = 5 without needing the theorem. For scenarios with both components present, the theorem would be used to find the resultant force.
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I have a question about those three forces. Let's say for example that f1x=0 and f1y=5 then f1=5 right? Or do I have to use the pathagorean therem to find f1 then it would be the square root of 5?
 
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The Pythagorean Theorem applies to right triangles. If one side is zero, you're no longer left with a triangle. The net force would be 5, since one component is zero. If both components were non-zero, you would use the Pythagorean Theorem.
 
In your example, since there is no x component, then fi = f1y =5. In general, however, use Pythagorus...f1 = sq rt of (f1x^2 + f1y^2) = sq. rt of (0^2 + 5^2) = sq rt of 25 = 5.
 
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