Finding Force Values Using Pythagorean Theorem

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SUMMARY

The discussion clarifies the application of the Pythagorean Theorem in calculating net forces in physics. When one force component, such as f1x, is zero, the net force equals the non-zero component, f1y. In this case, with f1x=0 and f1y=5, the net force f1 is definitively 5. The Pythagorean Theorem is only necessary when both components are non-zero, as demonstrated by the formula f1 = √(f1x² + f1y²).

PREREQUISITES
  • Understanding of vector components in physics
  • Knowledge of the Pythagorean Theorem
  • Basic algebra skills for manipulating equations
  • Familiarity with force concepts in physics
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  • Study the application of the Pythagorean Theorem in two-dimensional vector analysis
  • Explore examples of net force calculations in physics
  • Learn about vector addition and its graphical representation
  • Investigate scenarios involving multiple force components
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Students of physics, educators teaching vector analysis, and anyone looking to deepen their understanding of force calculations in two-dimensional space.

slammer
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I have a question about those three forces. Let's say for example that f1x=0 and f1y=5 then f1=5 right? Or do I have to use the pathagorean therem to find f1 then it would be the square root of 5?
 
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The Pythagorean Theorem applies to right triangles. If one side is zero, you're no longer left with a triangle. The net force would be 5, since one component is zero. If both components were non-zero, you would use the Pythagorean Theorem.
 
In your example, since there is no x component, then fi = f1y =5. In general, however, use Pythagorus...f1 = sq rt of (f1x^2 + f1y^2) = sq. rt of (0^2 + 5^2) = sq rt of 25 = 5.
 

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