A test rocket is launched by accelerating it along a 200.0-m incline at 1.25 m/s2 starting from rest at point A. The incline rises at 35.0° above the horizontal, and at the instant the rocket leaves it, its engines turn off and it is subject only to gravity (air resistance is ignored). Find:
a) the maximum height above the ground that the rocket reaches
b) the greatest horizontal range of the rocket beyond point A.
vx = v0cosα0
vy = v0sinα0
Basically, all the projectile motion formulas.
The Attempt at a Solution
Well, I don't even know how to start because I'm horrible at identifying which to find first. I assume I should find the initial velocity (v0) of the ball, then time, then find its max. height for a). But for part b), I have no clue. And I'm confused at whether to plug in 1.25 m/s2 or 9.8 m/s2 as the acceleration. How do I get to the answer of 124 m for a) and 280 m for b) Can someone walk me through this, please?
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