Finding height and time from angle and velocity

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SUMMARY

The discussion focuses on calculating the height, distance, and time of a toy rocket launched with an initial velocity of 30 units at an angle of 50 degrees. The key formulas provided are: horizontal distance traveled = 30 * (cos(50° in radians)) * t and height = 30 * (sin(50° in radians)) * t - (g/2) * t², where g represents the acceleration due to gravity. The conversion of degrees to radians is essential for accurate calculations.

PREREQUISITES
  • Basic understanding of projectile motion principles
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with unit conversions (degrees to radians)
  • Understanding of gravitational acceleration (g = 9.81 m/s²)
NEXT STEPS
  • Learn how to convert angles from degrees to radians
  • Study the equations of motion for projectile motion
  • Explore the effects of varying launch angles on projectile trajectories
  • Investigate the impact of initial velocity on maximum height and range
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Students studying physics, educators teaching mechanics, and hobbyists interested in basic aerodynamics and projectile motion calculations.

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A toy rocket is launched with a velocity of 30 at an angle of 50 deg. How would I find the height, distance, and time from that? Please help...
 
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Seeing that your question has not been shifted to the homework section, I’ll give you some idea. But the whole thing can be found in any high school mechanics book.

I assume that the toy rocket doesn’t have a propulsion system and is simply given an initial velo.
You have not given the unit of velo, so put the proper units for all the quantities.

If the angle with the horizontal is ‘x’ radians, then after time t,

horizontal dist traveled = 30*(cos x)*t, and

height of the rocket = 30*(sin x)*t –(g/2)*t^2.

Convert 50 degrees to radians.
 

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