Finding height of frictionless roller coaster

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Homework Help Overview

The discussion revolves around a physics problem involving a frictionless roller coaster. The scenario describes a passenger car starting from a height and moving through a vertical loop, with the goal of determining the height of the starting point above the bottom of the loop.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy principles to find the height, but questions arise regarding the definition of the reference point for potential energy. Some participants suggest reconsidering the setup of the equations and the assumptions made about the height.

Discussion Status

The discussion has progressed with the original poster arriving at a numerical answer but questioning the assumptions that led to their initial misunderstanding. Participants are engaging in clarifying the definitions and relationships between the points in the problem, particularly the reference point for height.

Contextual Notes

There is a noted confusion regarding the reference point for gravitational potential energy, which is critical for solving the problem correctly. The radius of the loop and the conditions for weightlessness at the top of the loop are also relevant factors under discussion.

Agent M27
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Homework Statement


Consider a frictionless roller coaster. The acceleration due to gravity is 9.8 ms-2. Passenger cars start at point A with zero initial speed, accelerate as they go down to a point B, swing around the vertical circular loop B-C-B of radius 15m, then go on towards further adventures. When a car goes through the top of the loop, point C, the passengers feel weightless. What is the height of the starting point A above the loops bottom, point B?


Homework Equations



Ugi+KEi=Ugf+KEf

mghi+.5mvi2=mghf+.5mv2f

v[tex]\geq[/tex][tex]\sqrt{gr}[/tex]

The Attempt at a Solution



Since the cart is at the top of the track and has zero initial speed the initial K.E. is canceled out. Also since the final location of the cart is the refrence point, the Ugf will be canceled out, so I am left with the following relationship:

mgh=.5mv2

V= 12.1244 m/s

h=[tex]\frac{v<sup>2</sup>}{2g}[/tex]
=7.5m

This answer is clearly incorrect because the radius of the loop alone is 15m. Any clues as to where I am missing the mark? Thanks in advance.

Joe
 
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Hello Joe,

Agent M27 said:
=7.5m

This answer is clearly incorrect because the radius of the loop alone is 15m.

Not necessarily incorrect. :smile: How did you define your variable 'h'? Take a closer look at how you set up your equations (which might be just fine the way they are, btw. [Although you left out the centripetal force part, but is how I assume you arrived at "v = 12.1244 m/s".]). Did you define 'h' with respect to the ground, or with respect to some other point? :cool:
 
I thought I defined h with respect to the ground, which is why I assumed the final gravitational potential to equal 0. I also made the assumption my starting point had to be higher than the loop just based on intuition, but apparently it doesn't have to be? By the way you worded your reply I am thinking that maybe I found the distance between point C (the top of the loop) and the starting point, is that correct? Thanks again.

Joe
 
Solved it, 37.5m! The issue was that I some how defined my reference point as point C... How did I make that mistake, which assumption was incorrect? Thanks again collinsmark.

Joe
 
Hello Joe,
Agent M27 said:
Solved it, 37.5m! The issue was that I some how defined my reference point as point C... How did I make that mistake, which assumption was incorrect? Thanks again collinsmark.
The only incorrect assumption was your:
mgh=.5mv2
That defines 'h' as the distance from point A to point C (point C is where v is being measured).

If you wanted to define 'h' as the height with respect to point B, the bottom of the loop, the equation should be,

(Potential energy at point A) = (kinetic energy at point C) + (potential energy at point C)
which is,

mgh = 0.5mv2 + mg(30 m)
 

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