Finding Height of Thrown Ball: Speed and Time

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SUMMARY

The discussion centers on calculating the speed required for a ball thrown at a 30.0° angle to reach the same height as a ball thrown straight upward, which is in the air for 1.54 seconds. The acceleration due to gravity is specified as 9.81 m/s². To find the height of the first ball, the equation DeltaX = Vi(DeltaT) + 1/2gDeltaT² is relevant. Once the height is determined, the speed for the second ball can be calculated using projectile motion principles.

PREREQUISITES
  • Understanding of kinematic equations, specifically DeltaX = Vi(DeltaT) + 1/2gDeltaT²
  • Knowledge of projectile motion concepts
  • Familiarity with the effects of gravity on motion
  • Basic algebra skills for solving equations
NEXT STEPS
  • Calculate the maximum height of the first ball using the kinematic equation
  • Learn how to apply projectile motion equations to find initial velocity
  • Explore the relationship between angle of projection and maximum height
  • Study the effects of gravity on vertical and horizontal motion in detail
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators seeking to explain these concepts effectively.

Leeee
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Homework Statement


A ball is thrown straight upward and returns to the thrower’s hand after 1.54 s in the air. A second ball is thrown at an angle of 30.0◦ with the horizontal.
The acceleration of gravity is 9.81 m/s2 .
At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?
Answer in units of m/s.


Homework Equations


DeltaX=Vi(DeltaT)+1/2gDeltaT^2
Any others unknown


The Attempt at a Solution


I've tried approaching the problem, but I can't seem to get started, first off, I'm unaware of how I would get the height of the first ball.
After I would get the height of the first ball, I know what I would do.
 
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