Finding Height of Thrown Ball: Speed and Time

[Leeee]

Homework Statement

A ball is thrown straight upward and returns to the thrower’s hand after 1.54 s in the air. A second ball is thrown at an angle of 30.0◦ with the horizontal.
The acceleration of gravity is 9.81 m/s2 .
At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?
Answer in units of m/s.

Homework Equations

DeltaX=Vi(DeltaT)+1/2gDeltaT^2
Any others unknown

The Attempt at a Solution

I've tried approaching the problem, but I can't seem to get started, first off, I'm unaware of how I would get the height of the first ball.
After I would get the height of the first ball, I know what I would do.

 

[Leeee]

Solved. Nevermind.