1. The problem statement, all variables and given/known data A 0.5kg rock is projected from the edge of the top of a building with an initial velocity of 13.7m/s at an angle 60o above the horizontal. The building is 6.89m in height . At what horizontal distance, x, from the base of the building will the rick strike the ground? Assume the ground is level and that the side of the building is vertical. The acceleration of gravity is 9.8m/s2. 2. Relevant equations dy = Voyt + 1/2at^2 Vx = dx/t 3. The attempt at a solution I have tried to find the vertical and horizontal component of the rock at its highest point. Using the vertical component, I found a time, which would be how long it took for the rock to get to its highest point from its original position. Then, I added the vertical component and the height of the building, and used that as the dy to find the time it takes for the rock to go from its highest point to the ground. I added the two times, and found a dx. My assignment is a quest on the UTexas site, so it would tell me when my answer is wrong. And here's a diagram: Thank you for your help!