Finding how long it will take the ball to reach 20m

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SUMMARY

The discussion focuses on calculating the time it takes for a baseball pitched horizontally at 160 km/h to travel 20 meters while determining how far it falls vertically during that distance. The correct approach involves using the formula for time, t = d/v, where d is distance and v is velocity. The user initially miscalculated the time by incorrectly multiplying distance and velocity without proper unit conversion, leading to an erroneous result. The correct time to reach home plate is approximately 0.125 seconds, and the vertical drop can be calculated using gravitational acceleration.

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1. The problem is the pitch was clocked at 160km/h and if a pitch were thrown horizontally with this velocity how far would the ball fall vertically by the time it reached home plate 20m away?



2. I used the average acceleration



3. t=d*average velocity
t= 20m * 160km/h
Convert 160km to m and then I got 20000 but it wrong bc the answer is 9.9 x 10^-1
 
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max1020 said:
1. The problem is the pitch was clocked at 160km/h and if a pitch were thrown horizontally with this velocity how far would the ball fall vertically by the time it reached home plate 20m away?



2. I used the average acceleration



3. t=d*average velocity
t= 20m * 160km/h
Convert 160km to m and then I got 20000 but it wrong bc the answer is 9.9 x 10^-1


It's good to use units as a sanity check of your calculations. Check the units on this calculation of yours, and then think about how you can re-arrange the equation to make the units work out...

"t= 20m * 160km/h"
 

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